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3 years ago

Which of the following statements is true about the distribution and storage process for natural gas

Chemistry

2 answers:

nlexa [21]3 years ago

7 0

<span>a.natural gas can be stored underground after processing</span>

OleMash [197]3 years ago

3 0

I almost a 100% sure it's A.

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Mandy made the following table describing the conditions required to form sleet and snow, but left something out. Which word sho

MakcuM [25]

I am not the best at this, but im pretty sure its below cloud

7 0

2 years ago

How many liters of space are in 4.00x10^22 of O2 occupy at STP

irinina [24]

Answer:

V O2 = 1.623 L

Explanation:

1 mol ≡ 6.022 E23 molecules

∴ molecules O2 = 4.00 E22 molecules

⇒ moles O2 = (4.00 E22 molecules O2)×(mol O2/6.022 E23 molecules)

⇒ moles O2 = 0.0664 moles

at STP:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

assuming ideal gas:

∴ V = RTn/P

⇒ V O2 = ((0.082 atm.L/K.mol)(298 K)(0.0664 mol))/( 1 atm)

⇒ V O2 = 1.623 L

5 0

3 years ago

A student analyzed an unknown sample that contained a single anion. The sample gave a yellow precipitated upon addition of a sol

kenny6666 [7]

<h3>Answer:</h3>

Anion present- Iodide ion (I⁻)

Net ionic equation- Ag⁺(aq) + I⁻(aq) → AgI(s)

<h3>Explanation:</h3>

In order to answer the question, we need to have an understanding of insoluble salts or precipitates formed by silver metal.

Additionally we need to know the color of the precipitates.

Some of insoluble salts of silver and their color include;

Silver chloride (AgCl) - white color
Silver bromide (AgBr)- Pale cream color
Silver Iodide (AgI) - Yellow color
Silver hydroxide (Ag(OH)- Brown color

With that information we can identify the precipitate of silver formed and identify the anion present in the sample.

The color of the precipitate formed upon addition of AgNO₃ is yellow, this means the precipitate formed was AgI.
Therefore, the anion that was present in the sample was iodide ion (I⁻).
Thus, the corresponding net ionic equation will be;

Ag⁺(aq) + I⁻(aq) → AgI(s)

4 0

3 years ago

Write down the structural formula for the monomer from which

Sati [7]

Answer:

Vinyl chloride is an organochloride with the formula H2C=CHCl that is also called vinyl chloride monomer (VCM) or chloroethene. This colorless compound is an important industrial chemical chiefly used to produce the polymer polyvinyl chloride (PVC).

Explanation:

7 0

2 years ago

Read 2 more answers

Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.

sammy [17]

A electrochemical reaction is said to be spontaneous, if $E^{0} cell is positive.$

Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s)

The cell representation of above reaction is given by;
  </span> $S^{2-}/S // Ni^{2+}/Ni$

Hence, $E^{0}cell = E^{0} Ni^{2+/Ni} - E^{0} S/S^{2-}$
we know that, ${E^{0} Ni^{2+}/Ni = -0.25 v$
and ${E^{0} S/ S^{2-} = -0.47 v$

Therefore, $E^{0} cell$ = - 0.25 - (-0.47) = 0.22 v

Since, $E^{0} cell$ is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2:
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
   $H_{2} / H^{+} // Pb^{2+} /Pb$

Hence, $E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}$
we know that, ${E^{0} Pb^{2+}/Pb = -0.126 v$
and ${E^{0} H_{2}/ H^{+} = -0 v$

Therefore, $E^{0} cell$ = - 0.126 - 0 = -0.126 v

Since,   $E^{0} cell$ is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3:
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
   $Cr/Cr^{2+} // Ag^{+}/Ag$

Hence, $E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}$
we know that, ${E^{0} Ag^{+}/Ag = -0.22 v$
and ${E^{0} Cr/ Cr^{2+} = -0.913 v$

Therefore, $E^{0} cell$ = - 0.22 - (-0.913) = 0.693 v

Since,   $E^{0} cell$ is positive, hence cell reaction is spontaneous

8 0

3 years ago

Read 2 more answers