Answer;
=28.09 amu
Explanation;
In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:
(460 X 100)/500 = 92%
If we do this for all three isotopes,
(460 × 25)/500 = 5 %
(460 × 15) /500 = 3%
-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).
Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:
= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)
= 25.74 amu + 1.449 amu + 0.8991 amu
= 28.09 amu
The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles
The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles
<h3>What is an atom?</h3>
An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.
- Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol
Using the relation:
- number of moles = mass/molar mass
The number of moles of H2O = 15.2 grams/18.02 g/mol
number of moles of H2O = 0.8435 moles
If the atomic mass of H and O are as follow:
- the atomic mass of H atom is = 1.00784 g/mol
- the atomic mass of O atom is = 15.999 g/mol
Then:
the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.
the number of H atoms = 0.8435 mol × 1.00784 g/mol
the number of H atoms = 0.850 moles
the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol
the number of O atoms = 13.50 moles
Learn more about atoms here:
brainly.com/question/25832904
Sugar and cytoplasm? maybe
