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Sedbober [7]
3 years ago
11

Au cours d'un orage le bruit de tonnerre met 7 secondes pour parvenir aux oreilles d'un observateur _1_ à quelle distance est to

mbée la foudre sachant que dans l'air le son se propage à la vitesse de 340 m/s . _2_ quel est le temps mis par la lumière de l'éclair pour franchir cette distance à l'aide de chronomètre courants
Physics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

2380\ \text{m}

7.93\times 10^{-6}\ \text{s}

Explanation:

t = Temps mis par la foudre pour parcourir la distance = 7 secondes

v = Vitesse du son dans l'air = 340 m / s

La distance est donnée par

s=vt\\\Rightarrow s=340\times 7\\\Rightarrow s=2380\ \text{m}

L'éclair est tombé à une distance de 2380\ \text{m}

c = Speed of light = 3\times 10^8\ \text{m/s}

Le temps est donné par

t=\dfrac{s}{c}\\\Rightarrow t=\dfrac{2380}{3\times 10^8}\\\Rightarrow t=7.93\times 10^{-6}\ \text{s}

Le temps mis par la lumière pour parcourir la distance est de 7.93\times 10^{-6}\ \text{s}.

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Answer:

Explanation:

height of tree = x

seven inches= 7

increaced by=+

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3 years ago
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When two waves in the same medium hit each other, the resulting displacement of the medium is
Irina-Kira [14]

Answer:

1. Either larger or smaller than the displacement of either wave acting alone, depending on the signs of the displacements of the two waves.

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4 years ago
66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown st
kozerog [31]

Answer:

a) t=1s

y = 10.1m

v=5.2m/s

b) t=1.5s

y =11.475 m

v=0.3m/s

c) t=2s

y =10.4 m

v=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

Explanation:

Conceptual analysis

We apply the free fall formula for position (y) and speed (v) at any time (t).

As gravity opposes movement the sign in the equations is negative.:  

y = vi*t - ½ g*t2 Equation 1

v=vit-g*t  Equation 2

y: The vertical distance the ball moves at time t  

vi: Initial speed

g= acceleration due to gravity

v= Speed the ball moves at time t  

Known information

We know the following data:

Vi=15 m / s

g =9.8 \frac{m}{s^{2} }

t=1s ,1.5s,2s

Development of problem

We replace t in the equations (1) and (2)  

a) t=1s

y = 15*1 - ½ 9.8*1^{2}=15-4.9=10.1m

v=15-9.8*1 =15-9.8 =5.2m/s

b) t=1.5s

y = 15*1.5 - ½ 9.8*1.5^{2}=22.5-11.025=11.475 m

v=15-9.8*1.5 =15-14.7=0.3m/s

c) t=2s

y = 15*2 - ½ 9.8*2^{2}= 30-19.6=10.4 m

v=15-9.8*2 =15-19.6=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

3 0
3 years ago
If
timama [110]

Answer:

Workdone = 1960 Joules.

Explanation:

Given the following data;

Mass = 5kg

Force = 49N

Height (distance) = 40m

To find the workdone;

Workdone = force * distance

Substituting into the equation, we have;

Workdone = 49*40

Workdone = 1960 Joules.

Therefore, the amount of work done on the bowling ball to lift it is 1960 Joules.

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What provides most of the force to allow the runners to move?
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When you are running the most important force that you should understand is friction. Friction is a force that opposes movement between two objects, but for runners friction makes you faster. Friction gives you a better and more efficient way to use your energy into speed.

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