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Sedbober [7]
3 years ago
11

Au cours d'un orage le bruit de tonnerre met 7 secondes pour parvenir aux oreilles d'un observateur _1_ à quelle distance est to

mbée la foudre sachant que dans l'air le son se propage à la vitesse de 340 m/s . _2_ quel est le temps mis par la lumière de l'éclair pour franchir cette distance à l'aide de chronomètre courants
Physics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

2380\ \text{m}

7.93\times 10^{-6}\ \text{s}

Explanation:

t = Temps mis par la foudre pour parcourir la distance = 7 secondes

v = Vitesse du son dans l'air = 340 m / s

La distance est donnée par

s=vt\\\Rightarrow s=340\times 7\\\Rightarrow s=2380\ \text{m}

L'éclair est tombé à une distance de 2380\ \text{m}

c = Speed of light = 3\times 10^8\ \text{m/s}

Le temps est donné par

t=\dfrac{s}{c}\\\Rightarrow t=\dfrac{2380}{3\times 10^8}\\\Rightarrow t=7.93\times 10^{-6}\ \text{s}

Le temps mis par la lumière pour parcourir la distance est de 7.93\times 10^{-6}\ \text{s}.

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Refer to the diagram shown below.

Neglect air resistance.
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The ball reaches a height of 3 m twice.
The first time it reaches 3 m height is 0.2815 s.

Part a.
The vertical velocity when t = 0.2815 s is
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The horizontal component of velocity is Vx = 15.973 m/s
The resultant velocity is 
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Answer:
The velocity at a height of 3.0 m  is 18.5 m/s (nearest tenth)

Part b.
The horizontal distance traveled is 
d = (15.973 m/s)*(0.2815 s) = 4.4964 m
Answer:
The horizontal distance traveled is 4.5 m (nearest tenth)

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