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scoray [572]
3 years ago
7

What’s are the different Types of chemical weathering

Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer:

Types of chemical weathering

1. Hydrolysis

2. Oxidation

3. Carbonation

4. Acid rain

5. Acids produced by lichens

Explanation:

Chemical weathering occurs when rocks undergo chemical reactions to form new minerals.

Hydrolysis : is when water dissolves minerals present in rocks forming new compounds.

Oxidation : is when oxygen reacts with rocks eg. rust formation

Carbonation : it uses an acid known as carbonic acid, it is important in the formation of many caves and sinkholes.

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Atoms of arsenic (As) are often added to silicon (Si) in a process called doping to change the conductivity of the silicon. How
alexandr1967 [171]
Silicon is a popular semi-conductor. The process of doping either creates an excess or lack of electrons. In the case of silicon, the dopant is arsenic which has greater valence electron than silicon. Arsenic then donates an electron resulting to an excess of electrons. A new type or better type of semi-conductor is created. Silicon conduct greater electricity.  

The best answer is the last option.
4 0
4 years ago
Read 2 more answers
How has the farming industry been affected by the use of fossil fuels?
irina [24]

Fossil fuels have increased the amount of crops harvested.

Explanation:

Fossil fuels have greatly increased the amount of crops affected in the farming industry. Farm mechanization is the use of machinery for farm works.

  • The bulk of machinery used on the farm are powered using fossil fuels obtained from organic matter of plants and animals.
  • The internal combustion engines of farm machines is fueled using crude oil products.
  • Tractors, harvesters, sprayers e.t.c used fossil fuels for their operations.

Learn more:

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7 0
3 years ago
What are the roles of producers, primary consumers, secondary consumers, tertiary consumers for the trophic levels in the energy
Nesterboy [21]
     This question is more for Biology than Chemistry, but the role of producers is to make energy (food) to be consumed. In a pyramid diagram, the producers would be at the bottom. Now going up the pyramid, the primary conumers are the first to consume producers and obtain energy from them. As you go up the pyramid, the secondary consumers will consume the primary consumers as a way to obtain energy, and the same goes for tertiary consumers towards secondaries.

As you go up the energy pyramid, you will notice a trend that there is less energy being obtained from each consumer. In other words, the producers will ALWAYS have more energy than the tertiary consumers.

I hope this answers your question. 
3 0
3 years ago
Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble
Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

           AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq) ............. (1)

     K_{sp} = [Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}

Reaction for the complex formation is as follows.

          Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq) ........... (2)

          K_{f} = \frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}

When we add both equations (1) and (2) then the resultant equation is as follows.

             AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq) ............. (3)

Therefore, equilibrium constant will be as follows.

                       K = K_{f} \times K_{sp}

                          = 1.0 \times 10^{8} \times 1.8 \times 10^{-10}

                          = 1.8 \times 10^{-2}

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of NH_{3} for complexation. This means we have to set

               [Ag^{+}] = [Cl^{-}]

                          = \frac{0.010 mol}{1 L}

                          = 0.010 M

For the net reaction, AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)

Initial :                             0.010         x                     0                           0

Change :                    -0.010         -0.020             +0.010                +0.010

Equilibrium :                   0            x - 0.020           0.010                 0.010

Hence, the equilibrium constant expression for this is as follows.

              K = \frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}

     1.8 \times 10^{-2} = \frac{0.010 \times 0.010}{(x - 0.020)^{2}}

             x = 0.0945 mol      

or,          x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of NH_{3} needed to be added is 0.095 mol.

3 0
4 years ago
Someone please answer i’ll give you brainly.
lina2011 [118]
Let's hope she didn't watch it without me or i will never be speaking to her again :))
4 0
3 years ago
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