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sp2606 [1]
3 years ago
13

If we eat a sandwich, why does it not come out as a

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
7 0

Answer:

Is this something logical? I don't know but it sounds absurd.

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

if we eat a sandwich it doesn't come out as a sandwich because we already ate it. its not going to come out whole if we already chewed it and digested it-

Explanation:

hope this helps, ỉdk if this is a real question, but if it is, then i guess use this answer??

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Nitrogen gas has a density of 4.566 g/L and liquid nitrogen density is 809.0 g/L.
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Explanation:

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What is 'Lo Salt' used for?
Igoryamba
It offers a route to reducing sodium intake.

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Give an example of at least one element made up of molecules and one compound made up of molecules.
zavuch27 [327]
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The carbon-14 radioisotope has proved most useful in:
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Calculate how many grams of the product form when 16.7 g of oxygen gas completely reacts with solid chromium. Assume that there
34kurt

<u>Answer:</u> The mass of product formed is 79.344 g.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of oxygen = 16.7 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen}=\frac{16.7g}{32g/mol}=0.522mol

The chemical reaction for the formation of chromium oxide follows the equation:

4Cr+3O_2\rightarrow 3Cr_2O_3

By Stoichiometry of the reaction:

3 moles of oxygen produces 3 moles of chromium oxide.

So, 0.522 moles of oxygen will produce = \frac{3}{3}\times 0.522=0.522mol of chromium oxide.

Now, calculating the mass of chromium oxide from equation 1, we get:

Molar mass of chromium oxide = 152 g/mol

Moles of chromium oxide = 0.522 moles

Putting values in equation 1, we get:

0.522mol=\frac{\text{Mass of chromium oxide}}{152g/mol}\\\\\text{Mass of chromium oxide}=79.344g

Hence, the mass of chromium oxide produced in the given reaction is 79.344 grams.

3 0
3 years ago
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