Answer:
no
Explanation:
Because I have lost and I dont know where is the worksheet
The correct answer is option 1. Be, Mg, and Ca is the correct order arranged in increasing atomic radius. This is predicted based on the periodic table. The atomic sizes increases as one moves downwards in the periodic table.
Protista .................................
Explanation:
It is given that r = 0.283 nm. As 1 nm =
.
Hence, 0.283 nm = ![0.283 \times 10^{-9} m](https://tex.z-dn.net/?f=0.283%20%5Ctimes%2010%5E%7B-9%7D%20m)
- Formula for coulombic energy is as follows.
![U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}](https://tex.z-dn.net/?f=U_%7Bcoulomb%7D%20%3D%20-1.748%20%5Cfrac%7Be%5E%7B2%7D%7D%7B4%20%5Cpi%20%5Cepsilon_%7Bo%7D%20r%7D)
where, e =
C
= ![8.85 \times 10^{-12}](https://tex.z-dn.net/?f=8.85%20%5Ctimes%2010%5E%7B-12%7D)
![U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}](https://tex.z-dn.net/?f=U_%7Bcoulomb%7D%20%3D%20-1.748%20%5Cfrac%7B%281.6%20%5Ctimes%2010%5E%7B-19%7D%5E%7B2%7D%7D%7B4%20%5Ctimes%203.14%20%5Ctimes%208.85%20%5Ctimes%2010%5E%7B-12%7D%20%5Ctimes%200.283%20%5Ctimes%2010%5E%7B-9%7D%7D)
= ![1.423 \times 10^{-18} J](https://tex.z-dn.net/?f=1.423%20%5Ctimes%2010%5E%7B-18%7D%20J)
- As 1 eV =
![1.6 \times 10^{-19} J](https://tex.z-dn.net/?f=1.6%20%5Ctimes%2010%5E%7B-19%7D%20J)
So, 1 J = ![\frac{1 eV}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%20eV%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
Hence, U = ![\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}](https://tex.z-dn.net/?f=%5Cfrac%7B1.423%20%5Ctimes%2010%5E%7B-18%7D%20J%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%20J%7D)
= 8.9 eV
- Also, 1 J =
![\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}](https://tex.z-dn.net/?f=%5Cfrac%7B10%5E%7B-3%7D%20kJ%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7Dmol%7D)
=
kJ/mol
Therefore, U =
kJ/mol
= ![2.37 \times 10^{-45} kJ/mol](https://tex.z-dn.net/?f=2.37%20%5Ctimes%2010%5E%7B-45%7D%20kJ%2Fmol)