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dimaraw [331]
3 years ago
5

What is the volume of 1.2 moles of water vapor at STP?

Chemistry
1 answer:
sladkih [1.3K]3 years ago
3 0
<span>Avogadro's law applies at STP where P is 1 atm and T is 273K. From Avogadro's law; 1 mole of gas takes up 22.4 L of volume at STP. I. e 1 moles = 22.4 L. Hence 1.2 moles of water vapor will take up. 1.2 * 22.4 = 26.88L. Or using ideal ga s eqn PV = NRT. We have P = 1 atm. N = 1.2 moles. R = 0.0821 L and T =273 K. So V = NRT/P.Then we have 1.2 * 0.0821 * 273 = 26.88L.</span>
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The unknown alcohol = 2-propanol

<h3>Further explanation</h3>

Given

volume = 50 ml

mass = 39.4 g

Required

The unknown alcohol

Solution

Density of sample :

= mass : volume

= 39.4 g : 50 ml

= 0.788 g/ml

The unknown alcohol at room temperature = liquid, so the unknown alcohol is 2-propanol because it has temperature range between -90 to 82 for liquid and the density = 0.788 g/ml

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