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uysha [10]
3 years ago
14

An animal shelter recently held an adoption event and found homes for 48 of their shelter animals. If they found home for 80% of

the animals during the event, how many animals were in the shelter before the event? [Type your answer as a number.]
Computers and Technology
2 answers:
vredina [299]3 years ago
4 0

Answer:

9.6

Explanation:

sergey [27]3 years ago
4 0

Answer:

Hi

Explanation:

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Write code to print the location of any alphabetic character in the 2-character string passCode. Each alphabetic character detec
serg [7]

Answer:

// here is code in java.

import java.util.*;

//class defintion

class Main

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // scanner object to read input

       Scanner s=new Scanner(System.in);

       String passcode;

       System.out.print("please enter the passcode:");

       // read string from user

       passcode=s.nextLine();

       // find first character

       char ch=passcode.charAt(0);

       // find second character

       char ch1=passcode.charAt(1);

       // if first character is alphabet

       if(Character.isLetter(ch))

       System.out.println("Alphabetic at 0:");

       // if second character is alphabet  

      else if(Character.isLetter(ch1))

       System.out.println("Alphabetic at 1:");

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create a scanner class object to read input from user.Read 2-character string

from user.Find the each character and check if it is a alphabet or not.If First

character is alphabet then print "Alphabetic at 0:" else if second character

is alphabet then print "Alphabetic at 1:".

Output:

please enter the passcode:b2

Alphabetic at 0:

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In the Dread Pirate Roberts case, U.S. Ulbricht, 31 F. Supp. 3D 54D (S.D.N.Y. 2014), one of the issues that the court addressed
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True.

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So, the following scenario is true about the case of Dread Pirate Roberts.

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What's usually kept in database?
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