The approximate speed of sound in dry (0% humidity) air, in meters per second, at temperatures near 0 °C, can be calculated from
Here
Temperature in Celsius
Replacing with our values we have that
Therefore the speed of sound in air at that temperature is 366.1m/s
To solve this problem we will start by defining the length of the shortest stick as 'x'. And the magnitude of the longest stick, according to the statement as
Both cover a magnitude of 8.32 ft, therefore
Now solving for x we have,
Therefore the shorter stick is 2.695ft long.
Answer:
1) The maximum jump height is reached at A.
2) The maximum center of mass height off of the ground is B.
3) The time of flight is C.
4) The distance of jump is B.
Explanation:
First of all we need to decompose velocity in its rectangular components, so
1) We use, , as we clear it for
and using the fact that
at max height, we obtain
2) We can use the formula for
, so
3) We can use the formula , to find total time of fligth, so
, as it is a second-grade polynomial, we find that its positive root is
4) Finally, we use , as it has an additional displacement of
due the leg extension we obtain,
, aprox