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valentina_108 [34]
3 years ago
6

How can you read a determine the masses

Chemistry
1 answer:
krok68 [10]3 years ago
4 0
I need you to explain the question
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The solubility of KClO3(s) in water increases as the
algol [13]
<span>Answer: option (1) solubility of the solution increases.
</span><span />

<span>Justification:
</span><span />

<span>The solubility of substances in a given solvent is temperature dependent.
</span><span />

<span>The most common behavior of the solubility of salts in water is that the solubiilty increases as the temperature increase.
</span><span />

<span>To predict with certainty the solubility at different temperatures you need the product solubility constants (Kps), which is a constant of equlibrium of the dissolution of a ionic compound slightly soluble in water, or a chart (usually experimental chart) showing the solubilities at different temperatures.
</span><span />

<span>KClO₃ is a highly soluble in water, so you do not work with Kps.
</span><span />

<span>You need the solubility chart or just assume that it has the normal behavior of the most common salts. You might know from ordinary experience that you can dissolve more sodium chloride (table salt) in water when the water is hot. That is the same with KClO₃.


</span><span>The solubility chart of KlO₃ is almost a straight line (slightly curved upward), with positive slope (ascending from left to right) meaning that the higher the temperature the more the amount of salt that can be dissolved.</span>
4 0
3 years ago
Read 2 more answers
What is the length of an average solar cycle? A. 5 years B. 11 years C. 22 years D. 10 years
Tems11 [23]
B. A solar cycle usually lasts 11 years.
4 0
2 years ago
How many grams of water do you need to weigh if a reaction requires 5 moles of h2o
rewona [7]

One mole of water weighs 18 grams. H₂O is composed of 2H= 2 and 1 0=16 adding gives you 18. number of moles= mass/ Relative Molecular Mass

Therefore, mass= Relative Molecular Mass×number of moles

                           = 18×5 moles

                           = 90 grams

5 0
3 years ago
A 25.00 ml solution of sulfuric acid H2SO4 is titrated to phenolphthalein end point with 27.00 ml of 1.700 M KOH
Nastasia [14]
<h3>Answer:</h3>

0.918 M

<h3>Explanation:</h3>

Assuming the question requires we calculate the Molarity of sulfuric acid:

We are given:

  • Volume of the acid, H₂SO₄ = 25.00 ml
  • Volume of the base, KOH = 27.00 mL
  • Molarity of the base, KOH is 1.70 M

We can calculate the molarity of the acid using the following steps;

<h3>Step 1: Write the chemical equation for the reaction.</h3>

The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.

Therefore, the balanced equation will be;

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the moles of the base, KOH </h3>

When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.

Number of moles = Molarity × Volume

                             = 1.700 M × 0.027 L

                              = 0.0459 moles

Thus, moles of KOH used is 0.0459 moles

<h3>Step 3: Determine the number of moles of the Acid, H₂SO₄</h3>

From the reaction, 1 mole of the acid reacts with 2 moles of KOH

Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2

Thus, moles of H₂SO₄ = Moles of KOH ÷ 2

                                     = 0.0459 moles ÷ 2

                                     = 0.02295 moles

<h3>Step 4: Calculate the molarity of the Acid </h3>

Molarity is the concentration of a solution in moles per liter

Molarity = Moles ÷ Volume

Molarity of the acid = 0.02295 moles ÷ 0.025 L

                                = 0.918 M

Thus, the molarity of the acid, H₂SO₄ is 0.918 M

5 0
3 years ago
A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike and the rider is 85 kg. Find the kinetic ener
krek1111 [17]

KE=3070.625 J

Height = 3.686 m

<h3>Further explanation</h3>

mass of bike+rider=85 kg

velocity = 8.5 m/s

\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 85\times 8.5^2\\\\KE=3070.625~J

Conservation of energy :

(KE+PE)₁ (downhill) = (KE+PE)₂ (up the hill)

PE₁=0⇒h=0

KE₂=0⇒v=0(stop), so equation becomes :

KE₁=PE₂

\tt KE_1=3070.625\\\\KE_1=mgh_2\\\\3070.625=85\times 9.8\times h\Rightarrow h=3.686~m

5 0
3 years ago
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