Answer:
See the answer below, please.
Explanation:
The equilibrium constant is defined as the relationship between products and reagents, each one elevated to their stoichiometric coefficients, in that of the given equation, the Kc is:
Kc= (NH4)^1/ (NH3)^1 x (HI)^1
NH4= products
NH3 and HI = reagents
Primary alkyl halides tend to undergo the SN2 reaction mechanism in nucleophilic substitution since there is less steric hindrance for nucleophilic attack and the carbocations that they form are not as stable as those formed from tertiary alkyl halides.
1-bromopentane > 1-bromo 2-methylbutane > <span>1-bromo-3-methylbutane</span>> 2-bromo 2-methylbutane
The enthalpies of formation of each of the compound involved in the chemical reaction presented above are given below:
CO2: -393.5 kJ/mol
CO: -99 kJ/mol
O2: 0 kJ/mol
As observed O2 will not have enthalpy of formation as it is a pure substance.
To calculate for the enthalpy of reaction,
enthalpy of formation of products - enthalpy of formation of reactants
= (-99 kJ/mol) - (-393.5 kJ/mol)
= 294.5 kJ/mol
ANSWER: 294.5 kJ/mol
the formula we is as follows:-
M1V1= M2V2
where
M1=1.2
V1=0.133l
V2=41l
M2=?
1.2 × 0.133 = 41 × M2
0.1596 = 41 × M2
M2 = 0.15960/41
M2 = 0.0038926829
Answer:
The chemical equilibrium of the system will be unaffected. The chemical equilibrium of the system will shift to the right to favor the forward reaction. The chemical equilibrium of the system will shift to the left to favor the reverse reaction. (I hope this helped!!)
