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Over [174]
3 years ago
8

An unknown metal displaces cadmium (Cd) from solution but does not displace chromium (Cr). Using the activity series, determine

the unknown metal.
lead (Pb)
manganese (Mn)
iron (Fe)
zinc (Zn)
cobalt (Co)
Chemistry
2 answers:
Lesechka [4]3 years ago
8 0

Answer : The correct option is, iron (Fe)

Explanation :

The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions.

In the single displacement reaction, the most reactive metal displaces the least reactive metal.

From the reactivity series we conclude that zinc and magnesium are more reactive metal than cadmium and chromium metal. So, both can easily displace the cadmium and chromium metal from the solution. So, zinc and magnesium will exclude from the answer.

The metal lead and cobalt are least reactive than cadmium and chromium metal. So, both can not displace cadmium and chromium metal from the solution. So, lead and cobalt will also exclude from the answer.

The metal iron is more react metal than cadmium metal but less reactive than chromium metal. So, iron metal can not displace chromium metal but it can displace easily cadmium metal.

Hence, the correct option is, iron (Fe)

adell [148]3 years ago
3 0
I found this is the order of activity in Internet

Mn>Zn>Cr>Fe>Cd>Co>Ni>Pb

You can see that Fe is between Cr and Cd

Cr is more active than Fe and Fe is more active than Cd.

The Fe will displace Cd but not Cr.

Answer:Fe
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What is the mass in grams of 1.00 x 10 24 atoms of Mn?
Alex17521 [72]
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0
3 years ago
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