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Over [174]
3 years ago
8

An unknown metal displaces cadmium (Cd) from solution but does not displace chromium (Cr). Using the activity series, determine

the unknown metal.
lead (Pb)
manganese (Mn)
iron (Fe)
zinc (Zn)
cobalt (Co)
Chemistry
2 answers:
Lesechka [4]3 years ago
8 0

Answer : The correct option is, iron (Fe)

Explanation :

The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions.

In the single displacement reaction, the most reactive metal displaces the least reactive metal.

From the reactivity series we conclude that zinc and magnesium are more reactive metal than cadmium and chromium metal. So, both can easily displace the cadmium and chromium metal from the solution. So, zinc and magnesium will exclude from the answer.

The metal lead and cobalt are least reactive than cadmium and chromium metal. So, both can not displace cadmium and chromium metal from the solution. So, lead and cobalt will also exclude from the answer.

The metal iron is more react metal than cadmium metal but less reactive than chromium metal. So, iron metal can not displace chromium metal but it can displace easily cadmium metal.

Hence, the correct option is, iron (Fe)

adell [148]3 years ago
3 0
I found this is the order of activity in Internet

Mn>Zn>Cr>Fe>Cd>Co>Ni>Pb

You can see that Fe is between Cr and Cd

Cr is more active than Fe and Fe is more active than Cd.

The Fe will displace Cd but not Cr.

Answer:Fe
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A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net
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Answer:

See explanation

Explanation:

The molecular equation shows all the compounds involved in the reaction.

The molecular equation is as follows;

2NaF(aq) + Pb(NO3)2(aq) -------> PbF2(s) + 2NaNO3(aq)

The complete ionic equation shows all the ions involved in the reaction

The complete ionic equation;

2Na^+(aq) + 2F^-(aq) + Pb^2+(aq) + 2NO3^-(aq) -------->PbF(s) + 2Na^+(aq) +2NO3^-(aq)

The net Ionic equation shows the ions that actually participated in the reaction

The net ionic equation is;

2F^-(aq) + Pb^2+(aq)--------> PbF(s)

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