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Over [174]
3 years ago
8

An unknown metal displaces cadmium (Cd) from solution but does not displace chromium (Cr). Using the activity series, determine

the unknown metal.
lead (Pb)
manganese (Mn)
iron (Fe)
zinc (Zn)
cobalt (Co)
Chemistry
2 answers:
Lesechka [4]3 years ago
8 0

Answer : The correct option is, iron (Fe)

Explanation :

The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions.

In the single displacement reaction, the most reactive metal displaces the least reactive metal.

From the reactivity series we conclude that zinc and magnesium are more reactive metal than cadmium and chromium metal. So, both can easily displace the cadmium and chromium metal from the solution. So, zinc and magnesium will exclude from the answer.

The metal lead and cobalt are least reactive than cadmium and chromium metal. So, both can not displace cadmium and chromium metal from the solution. So, lead and cobalt will also exclude from the answer.

The metal iron is more react metal than cadmium metal but less reactive than chromium metal. So, iron metal can not displace chromium metal but it can displace easily cadmium metal.

Hence, the correct option is, iron (Fe)

adell [148]3 years ago
3 0
I found this is the order of activity in Internet

Mn>Zn>Cr>Fe>Cd>Co>Ni>Pb

You can see that Fe is between Cr and Cd

Cr is more active than Fe and Fe is more active than Cd.

The Fe will displace Cd but not Cr.

Answer:Fe
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Which aldehyde is an intermediate in the reduction of ethyl benzoate with lithium aluminum hydride?
garri49 [273]

Answer:

tetrahedral aldehyde

Explanation:

  1. The reaction begins with a hydride nucleophile reacting with the ester carbonyl carbon to form the tetrahedral intermediate.
  1. The carbonyl reforms to produce an aldehyde with the loss of the alkoxide ion.
  2. The resulting aldehyde undergoes a subsequent reaction with a hydride nucleophile to form another tetrahedral intermediate. The carbonyl is not able to reform, because there are no stable leaving groups.
  3. Therefore, the tetrahedral intermediate is protonated to produce a primary alcohol.
6 0
3 years ago
How does the volume of water change the solubility of sodium chloride in simple words?
kupik [55]

Answer:

When sodium chloride dissolves in water to make a saturated solution there is a 2.5 per cent reduction in volume. ... The solubility of salt does not change much with temperature, so there is little profit in using hot water.

3 0
3 years ago
How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦C and 1.000 atm pressure to form CO2(g). All of
iogann1982 [59]

Answer:

T₂ = 43.46 °C  

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,    

m_{water}\times C_{water}\times \Delta T=Q

For water:  

Mass of water  = 5100 g

Specific heat of water = 4.18 J/g°C  

T₁ = 25 °C  

T₂ = ?

Q = 393500 J

So,

5100\times 4.18\times (T_2-25)=393500  

T₂ = 43.46 °C  

6 0
3 years ago
For the reaction of aqueous strontium chloride and lithium sulfate, write the balanced molecular equation
Igoryamba
SrCl2 + Li2(SO4) —> 2LiCl + Sr(SO4)
7 0
3 years ago
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