The total moment of inertia of the system is the sum of the moment of inertia of the disk plus the moment of the inertia of the person.
The moment of inertia of a uniform disk is Id = [1/2] Md * (R^2)
And the moment of inertia of the person standing on the rim of the disk is Ip = Mp(R^2).
So the total amounf ot inertia is: I = Id + Ip = [1/2]Md(R^2) + Mp(R^2).
There you only need to plug in the values that you are given for the problem:
If Md = 193 kg, Mp = 77 kg, and R = 2.07 m
I = [1/2]*193kg*(2.07m)^2 + 77kg * (2.07m)^2 = 743.43 kg * m^2
Answer: 743.43 kg * m^2
(a)
<span>F= qE </span>
<span>F sin 30.0° = mg </span>
<span>= 0.0026(10) </span>
<span>= 0.026 N </span>
<span>F = 0.052 N </span>
<span>E = F/q = 0.052 / 60µ = 867 N/C </span>
<span>(b) </span>
<span>T = F cos 30.0° </span>
<span>= 0.0450 N</span>
Answer:
t= 24080 s
Explanation:
Given that
Current in the wire ,I = 4 A
The charge ,q = 6.02 x 10²³ e C
We know that
I=Current
q=Charge
t=time
Now by putting the values in the above equation we get'
t= 24080 s
Answer:
Electron shell
Nucleus
Neutrons
Explanation:
An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.
- Protons are the positively charged particles. Neutrons do not carry any charges.
- Both protons and neutrons are found in the tiny nucleus at the center of that atom.
- The electrons are negatively charged.
- They are found outside the nucleus in electronic shells.
Answer:
E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2
E = 1/2 M V^2 (1 + I / (M R^2))
For a cylinder I = M R^2
For a sphere I = 2/3 M R^2
E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2
E(sphere) = 1 + 2/3 = 1.67
E(cylinder) / E(sphere) = 2 / 1.67 = 1.2
The cylinder initially has 1.20 the energy of the sphere
The PE attained is proportional to the initial KE
H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE
