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nika2105 [10]
2 years ago
5

a rifle is fired and recoils when the bullet leaves the gun. this is an example of newton's 3rd law. the force on the bullet is.

-the same as -smaller than - greater than
Physics
2 answers:
pentagon [3]2 years ago
6 0

Explanation:

The third law of newton states that for an action there exists an equal and opposite reaction. One of the example of third law of motion is "a rifle is fired and recoils when the bullet leaves the gun".

The two forces acting on the object are action force and the reaction force. The magnitude of both forces are equal but act in opposite direction.

Hence, the force on the bullet is the same but the direction of force is opposite.

Alex_Xolod [135]2 years ago
3 0
The force of the bullet is the same.
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WILL NAME THE BRAINLIEST! An airplane undergoes the following displacements: It first flies 72 km in a direction of 30° East of
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Answer:

82.1 km

Explanation:

We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:

A_x = (72) sin 30^{\circ} =36.0 km\\A_y = (72) cos 30^{\circ} = 62.4 km

Vector B is 48 km south, so:

B_x = 0\\B_y = -48

Finally, vector C:

C_x = -(100) cos 30^{\circ} =-86.6 km\\C_y = (100) sin 30^{\circ} = 50.0 km

Now we add the components along each direction:

R_x = A_x + B_x + C_x = 36.0 + 0 +(-86.6)=-50.6 km\\R_y = A_y+B_y+C_y = 62.4+(-48)+50.0=64.6 km

So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is

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4 0
2 years ago
Suppose that you observe light emitted from a distant star to be at a wavelength of 525 nm. The wavelength of light to an observ
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Answer:

The velocity of the star is 0.532 c.

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Given that,

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We need to calculate the velocity

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Put the value into the formula

525=\sqrt{\dfrac{c+v}{c-v}}\times950

\dfrac{c+v}{c-v}=(\dfrac{525}{950})^2

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v(1+0.305)=c(0.305-1)

v=\dfrac{0.305-1}{1+0.305}c

v=−0.532c

Negative sign shows the star is moving toward the observer.

Hence, The velocity of the star is 0.532 c.

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