<span>Given:
Hmax (distance) = 50.0m
v</span>₀ = <span>70.0m/s
Required:
what angle should the arrow make with the horizontal as it is being shot
Solution:
Hmax = v</span>₀²sin²θ / 2g
sin²θ = 2gHmax / v₀²
sin²θ = 2 (9.81 m/s²) (50m) / (70 m/s)²
sin²θ = 0.200
θ = 26.56°
Answer:
a
x-component 
y-component 
b
Magnitude 
direction is 
Explanation:
From the question we are told that
The first vertical distance is 
The first horizontal distance is 
The second vertical distance is 
Generally the displacement is
x-component
y-component
Generally the helicopters displacement is mathematically evaluated as
The direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as
![\theta = tan ^{-1}[ \frac{48}{20}]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20tan%20%5E%7B-1%7D%5B%20%5Cfrac%7B48%7D%7B20%7D%5D)
=> ![\theta = tan ^{-1}[ 2.4 ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20tan%20%5E%7B-1%7D%5B%202.4%20%5D)
=>
Answer:
From smallest ratio to the largest ratio:
Coasting Universe - Critical Universe - Recollapsing Universe(From left to right)
Explanation:
The coasting universe is one that expands at a constant rate given by the Hubble constant throughout all of cosmic time. It has a ratio of actual density to critical density that is less than 1
The critical universe is one that is at balance with no expansion .I.e. the actual density and the critical density are equal, which makes the ratio of actual density to critical density to be equal to 1
Recollapsing Universe: The expansion of the universe reverses in the future and the universe eventually recollapses. The recollapsing universe has the ratio of the actual density to the critical density to be greater than 1
False. Since the forces are pulling in equal and opposite directions, the net force is 0.
