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Ludmilka [50]
3 years ago
10

PLEASE HELP THE question on picture

Physics
1 answer:
Gnoma [55]3 years ago
7 0

Vertical:

(20 m/s) sin(25º) ≈ 8.45 m/s

Horizontal:

(20 m/s) cos(25º) ≈ 18.1 m/s

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A parallel-plate capacitor is connected to a battery until it is fully charged. Then, the capacitor is disconnected from the bat
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Answer:

The potential between the plates will decrease.

Explanation:

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Furthermore, the dielectric effect will make the electric field of the charged capacitor which is not connected to a source of supply to decrease.

Now, when the battery is removed, the charge Q remains constant and Capacity C will increase.

Formula for the potential difference is here;

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Since the numerator Q is constant and the denominator C increases, it means the potential difference V will decrease

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