Answer:
The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer
Step-by-step explanation:
* The distance between any to points (x1 , y1) , (x2 , y2) is
- d = √[square the difference of x- coordinates plus
square the difference of y-coordinates]
∴ d = √[(x2 - x1)² + (y2 - y1)²] or
∴ d² = (x2 - x1)² + (y2 - y1)²
* x2 - x1 is the horizontal distance (h) and y2 - y1
is the vertical distance (v)
- By using Pythagoras theorem
∴ d = √[h² + v²]
∵ The two points are (p , q) and (m , n)
- Put x1 = m and y1 = n
- Put x2 = p and y2 = q
∴ d² = (p - m)² + (q - n)²
∴ d = √[(p - m)² + (q - n)²]
∴ The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer
