Answer:
living things are found in air, water, and soil.
Explanation:
Yes dams are made wider at the bottom because the pressure of the water pressure is greater there
Answer:
Explanation:La ecuación de Van der Waals es una ecuación de estado de un fluido compuesto de partículas con un tamaño no despreciable y con fuerzas intermoleculares, como las fuerzas de Van der Waals. La ecuación, cuyo origen se remonta a 1873, debe su nombre a Johannes van der Waals, quien recibió el premio Nobel en 1910 por su trabajo en la ecuación de estado para gases y líquidos, la cual está basada en una modificación de la ley de los gases ideales para que se aproxime de manera más precisa al comportamiento de los gases reales al tener en cuenta su tamaño no nulo y la atracción entre sus partículas.
Answer:
The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.
Explanation:
Given:
Mass of the piano = 190 kg
Inclined angle = 18 degree
Considering gravity, = 9.8
And
Using, and
<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>
We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.
a.
When the man pushes it parallel to the incline.
Balancing the forces as .
⇒
⇒
⇒ Here it is negative as the force is acting downward.
⇒ Plugging the values of mass and angle .
⇒
⇒ N
b.
When the force is parallel to the floor.
⇒
⇒
⇒ Plugging the values.
⇒
⇒ N
So,
The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.
If the primary wire's power is 10 A and one branch's power is 4 A, another branch's power will be 6A.
According to Kirchhoff's current law (KCL), the total current flowing through a parallel route circuit's junction equals the total current flowing away from it.
Provided that one of the two branches through which power exits the intersection has a flow of 4A, and also that the junction's overall flow entering it is 10A, the entire current going the junction should be 10A.
Consequently, the second wire's power may be expressed as;
I = I1+ I2 [ where I= total current (10A);
I1= current in one branch (4A) &
I2= current in another branch]
⇒I2 = I - I1
⇒I2 = 10A - 4A
⇒I2 = 6A
Therefore, it can be concluded that when the primary wire bears 10A power having 4A in one of its branches, another branch carries 6A power.
Learn more about Kirchhoff's law here:
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