Answer:
<u><em>To answer this question we assumed that the area units and the thickness units are given in inches.</em></u>
The number of atoms of lead required is 1.73x10²³.
Explanation:
To find the number of atoms of lead we need to find first the volume of the plate:

<u>Where</u>:
A: is the surface area = 160
t: is the thickness = 0.002
<u><em>Assuming that the units given above are in inches we proceed to calculate the volume: </em></u>
Now, using the density we can find the mass:

Finally, with the Avogadros number (
) and with the atomic mass (A) we can find the number of atoms (N):
Hence, the number of atoms of lead required is 1.73x10²³.
I hope it helps you!
Answer: Laplace equation provides a linear solution and helps in obtaining other solutions by being added to various solution of a particular equation as well.
Inviscid , incompressible and irrotational field have and basic solution ans so they can be governed by the Laplace equation to obtain a interesting and non-common solution .The analysis of such solution in a flow of Laplace equation is termed as potential flow.
Answer:
Explanation:
relating to, measuring, or measured by the quantity of something rather than its quality.Often contrasted with qualitative.
Answer:
C
Explanation:
Hydraulic systems can increase or decrease the force applied to them. To make the force larger, the pressure is applied to a larger area. For example, if a 100-N force is applied to the left cylinder in (Figure) and the right cylinder has an area five times greater, then the output force is 500 N.
Answer:
The required bulk modulus is
Psi. So, the answer is non of these.
Explanation:
Change in pressure of the fluid is directly proportional to the volumetric strain. The constant of proportionality is the bulk modulus of the fluid.
Step1
Given:
Percentage change in volume is 1%.
Change in pressure is 10000 Psi.
Calculation:
Step2
Volumetric strain is calculated as follows:


Step3
Bulk modulus is calculated as follows:
\frac{\bigtriangleup V}{V}=0.01


K = 1000000 Psi.
Thus, the required bulk modulus is
Psi.