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3 years ago

Alchemy was practiced _____.

Chemistry

1 answer:

Aleksandr [31]3 years ago

6 0

The answer is c maybe

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Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after

Alenkinab [10]

Answer:

For a: The number of moles of air present in the RV is 0.047 moles

For b: The number of molecules of gas is $2.83\times 10^{22}$

Explanation:

For a:

To calculate the number of moles, we use the equation given by ideal gas follows:

$PV=nRT$

where,

P = pressure of the air = 1.00 atm

V = Volume of the air = 1200 mL = 1.2 L (Conversion factor: 1 L = 1000 mL)

T = Temperature of the air = $37^oC=[37+273]K=310K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of air = ?

Putting values in above equation, we get:

$1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol$

Hence, the number of moles of air present in the RV is 0.047 moles

For b:

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 0.047 moles of air will contain $(0.047\times 6.022\times 10^{23})=2.83\times 10^{22}$ number of gas molecules.

Hence, the number of molecules of gas is $2.83\times 10^{22}$

7 0

3 years ago

The line of longitude used as the origin in a system of coordinates

3241004551 [841]

Yup, that is correct.

7 0

3 years ago

Will mark Brainly us if you help me

ohaa [14]

Answer: ok, its C

Explanation: I used D=26.4* 3 to calculat it

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3 years ago

What is a chemical change

navik [9.2K]

Isn't a chemical change like something that's not a physical change or physically changed but is something that uses natural chemicals? that's my guess sorry if it's wrong I think I'm wrong though

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3 years ago

Read 2 more answers

A substance freezes at -58 celcius. Therefore a substance melts at: ________________

Liono4ka [1.6K]

-58 °C
The melting point is the same as the freezing point.

4 0

3 years ago