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3 years ago

Which is one way scientists indicate how precise and accurate there experimental measurements are

1 answer:

8 0

They do the method 3 times to be sure. Because if you do it once, that could mean anything. If you do it twice, it may or may not have the same result. If you do it 3 times and it matches one of the previous answers, then it's likely that it's correct.

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C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F. Calculate the equivalent capacitance

grin007 [14]

The equivalent capacitance between A and B points is 2.5F.

<h3>What is parallel plate capacitor?</h3>

The two parallel plates placed at a distance apart used to store charge when electric supply is on.

The capacitance of a capacitor is given by

C = ε₀ A/d

From the given circuit C1, C2 and C3, C4 are in parallel C1=4F, C2=4F, C3=2F, C4=4F, C5= 9.2 F

C1, C2 = 4 +4 =8F

C3, C4 = 2 +4 =6F

Now , all capacitors are in series.

Total equivalent capacitance is
1 / Ceq = 1/ 8 +1/6 +1/ 9.2

Ceq = 2.5 F

Thus, the equivalent capacitance between A and B points is 2.5F.

Learn more about parallel plate capacitor.

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6 0

2 years ago

A film badge worn by a radiologist indicates that she has received an absorbed dose of 2. 5 x 10-6 gy. the mass of the radiologi

Anestetic [448]

Energy absorbed by the radiologist is 1.775*10^-6J.

To find the answer, we have to know about the radiation.

<h3>How much energy has she absorbed?</h3>

We have the expression for dose of absorption as,

$D=\frac{E}{m}$

where; E is the energy absorbed and m is the mass of the body.

From the above expression, substituting appropriate values given in the question, we get,

$E=D*m=2.5*10^{-6}J/kg*71kg=1.775*10^{-4}J$

Thus, we can conclude that, the Energy absorbed by the radiologist is 1.775*10^-6J.

<h3 />

Learn more about the radiation here:

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4 0

1 year ago

What is the velocity of an object with a kinetic energy of 800 J and a mass of 12 kg?

Elis [28]

K.E = 1/2 mv²

800 = 1/2 ×12 ×v²

800 = 6 v²

800 / 6 = v²

= 133.4 =v²

√133.4 = √v²

11.5 = v²

I hope this answer is correct.

3 0

3 years ago

a particle moves along the x axis with an acceleration of a=18t, where a has units if m/s2. if the particle at time t=0 is at th

ludmilkaskok [199]

Answer:

Position at t= 4 seconds is 144 m

Explanation:

It is given that acceleration, a = 18 t, where t is the time.

We know that Velocity, $v = \int { a} \, dt$

Substituting value of a,

Velocity, $v = \int {18t} \, dt=\frac{18t^2}{2} +c=9t^2+c$

We know that at t = 0, v = -12 m/s

So, $9*0^2+c=-12\\ \\ c=-12m/s$

So velocity, $v = (9t^2-12)m/s$

We also know that displacement, $x = \int { v} \, dt$

Substituting value of v,

Displacement, $x=\int {(9t^2-12)} \, dt=\frac{9t^3}{3} -12t+c=3t^3-12t+c$

We know that at t = 0, particle is at origin, x =0.

So, $0=3*0^3-12*0+c\\ \\ c=0$

Displacement, $x = 3t^3-12t$

At t = 4 seconds

$x = 3*4^3-12*4=192--48=144m$

Position at t= 4 seconds is 144 m

4 0

3 years ago

Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has

k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0

2 years ago