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kifflom [539]
3 years ago
15

A coin purse contains d dimes and q quarter's. There are 20 coins in the purse and the total value of the coins is $4.25. Which

coin system of equations represent this situation? A. d+q=4.25, 0.1d+0.25q=20. B.d+q=20, 0.1d+0.25q=4.25. c. d+q=20, d+q=4.25 ​
Physics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

a

Explanation:

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A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that ti
Sergeeva-Olga [200]

Acceleration  =  (change in speed)  /  (time for the change)

                       =      (49 m/s)   /   (5 seconds)

                       =       (49 / 5)  m/s  /  s

                       =            9.8 m/s² 
8 0
3 years ago
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A student swings a container of water in a vertical circle of radius 1.0 m. Calculate the minimum speed of the container so that
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Answer:

Explanation:

The centripetal acceleration requirement must equal gravity at the top of the circle

mg = mv²/R

  v = √Rg

  v = √(1.0(9.8))

  v = 3.1304951...

  v = 3.1 m/s

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Which phenomenon would cease to exist in the absence of this axial tilt?
konstantin123 [22]
If the Earth didn't tilt then we wouldn't have seasons.
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A lightbulb has a power of 100 W and is used for 4 hours. A microwave has a power of 1200 W and is used for 5 minutes. How much
ladessa [460]

Answer:

a. E=1440KJ

b. E=360KJ

c. E=1.8 J

Explanation:

I have the power (Watts) is expressed as Energy (Joules) / Time (seconds), also I have to1hour * \frac{60min}{1hour}*\frac{60s}{1min}\\1h=3600s

so, for the lightbulb

100W= \frac{Energy}{3600s*4}\\Energy=100W*14400s\\ E=1440000J =1440KJ

Analogously, for the microwave

1200W= \frac{Energy}{60s*5}\\Energy=1200W*300s\\ E=360000J =360KJ

Now, I have to express the efficiency as Heat energy / power * 100 so1.8= \frac{Heat Energy}{100W}*100\\Heat Energy=1.8J

Done

4 0
4 years ago
A 25.0 kg projectile is fired by accelerating it with an electromagnetic rail gun on the earth's surface. the rail makes a 30.0
stich3 [128]

(a)

The work done on the projectile is 9375 joule.

The work on the projectile is calculated as

W=F×d

=1250×7.5

=9375 joule

(b)

The speed of the projectile after 7.5 m is 27.38 m/s

First we need to find out the acceleration of the projectile

F=m×a

1250=25×a

a=50 m/s^{2}

Now the velocity of the projectile after 7.5 m is calculated as

v^2=u^2+2a×s

v^2=0+2×50*7.5

v=27.38 m/s

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