Answer:
C) unbalanced
Explanation:
Equal forces acting in opposite directions are called balanced forces. Balanced forces acting on an object will not change the object's motion. When you add equal forces in opposite direction, the net force is zero.
Answer:
A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West
Explanation:
A) For this exercise we must use the expression of Faraday's law for a moving body
fem = 
fem =
- d (B l y) / dt = - B lv
B = 
we calculate
B = - 7.9 10⁻⁴ /(0.73 20)
B = 5.4 10⁻⁵ T
B) to determine which side of the bar is positive, we must use the right hand rule
the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.
Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West
Answer:
true i think
Explanation:
The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 10.2 sound C is louder than sound B. The vibration of a source sets the amplitude of a wave.
Answer:
The Pressure is 0.20 MPa.
(b) is correct option.
Explanation:
Given that,
Change in volume = 9.05%
{tex]\dfrac{\Delta V}{V_{0}}=0.0905[/tex]
We know that.
The bulk modulus for water

We need to calculate the pressure difference
Using formula bulk modulus formula





Hence, The Pressure is 0.20 MPa.
Answer:
Therefore,
The magnitude of the force per unit length that one wire exerts on the other is

Explanation:
Given:
Two long, parallel wires separated by a distance,
d = 3.50 cm = 0.035 meter
Currents,

To Find:
Magnitude of the force per unit length that one wire exerts on the other,

Solution:
Magnitude of the force per unit length on each of @ parallel wires seperated by the distance d and carrying currents I₁ and I₂ is given by,

where,

Substituting the values we get


Therefore,
The magnitude of the force per unit length that one wire exerts on the other is
