Brainless if correct

Chemistry

2 answers:

Law Incorporation [45]3 years ago

8 0

Answer:

a or c

Explanation:

nadya68 [22]3 years ago

4 0

Answer:

The answer is A

Explanation:

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the half-life of chromium 51 is 28 days if the sample contained 510 grams how much chromium would remain after 86 days

Anni [7]

Answer: 3.285714285714286 I believe this is what it is

Explanation:

You have to divide 50 by 28 then times it by 510 then divide by 86

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3 years ago

How many grams of the reactant water is needed to make 800.00g of calcium carbonate? The balance equation is:

Ket [755]

Answer:

432.1 grams of water

Explanation:

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3 years ago

What is the weight of dark matter

Ostrovityanka [42]

Answer:

Knowing this, researchers from the University of Southern Denmark decided to investigate the size of these hypothetical hidden particles. According to the team, dark matter could weigh more than 10 billion billion (10^9) times more than a proton.

Explanation:

If this is true, a single dark matter particle could weigh about 1 microgram, which is about one-third the mass of a human cell (a typical human cell weighs about 3.5 micrograms), and right under the threshold for a particle to become a black hole.

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3 years ago

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What is the ground state electron configuration for magnesium?

Stella [2.4K]

Magnesium :

<span>[Ne] 3s²</span>

Answer A

hope this helps!

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3 years ago

A chemist adds of a sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemi

schepotkina [342]

This is a incomplete question.The complete question is:

A chemist adds 180.0 ml of a 1.77 mol/L of sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer: 50.4 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$ .....(1)