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3 years ago

13

The largest number of neurons within the brain and spinal cord are responsible for the central nervous system's complex internal

communications and intervene between inputs and outputs. These are the _____.

1 answer:

GREYUIT [131]3 years ago

3 0

Answer: Interneurons.

These interneurons transmit impulses to other neurons and thus form a part of the reflux arc.

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Which of the following best describes the suns size compared with other stars?

Rufina [12.5K]

1) D: enormous
2) D: gravity

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3 years ago

Two objects feel 200 N of force due to gravity between them. If the mass of one object was doubled, what would be the new force

viktelen [127]

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3 years ago

An airplane pilot sets a compass course due west and maintains a speed of 220 km/h. after flying for a half hour she finds herse

timurjin [86]

The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.

so airspeed due west is = net speed - speed of plane = 240-220= 20 km/h.

airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.

the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h

the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.

if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.

so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.

the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.

5 0

3 years ago

Read 2 more answers

a 60g tennis ball travelling at 30m/s hi a wall and bounce back at 20m/s.calculate (a)momentum of the ball before impact (b)mome

frez [133]

Explanation:

the formula for momentum is denoted by p=mv where p is momentum, m is mass and v is velocity. thus, the velocity before impact would be 0.060 x 30 = 1.8 kg/ms

the second one would just be 0.060 x 20 0.72kg/ms

I'm not 100 percent sure this is correct but yeah

6 0

3 years ago

A certain elastic conducting material is stretched into a circular loop of 1.6 cm radius. It is placed with its plane perpendicu

inysia [295]

Answer:

Induced emf in the loop is 0.0603 volts.

Explanation:

It is given that,

Radius of the circular loop, r = 1.6 cm = 0.016 m

Magnetic field, B = 0.8 T

When released, the radius of the loop starts to shrink at an instantaneous rate of 75.0 cm/s, $\dfrac{dr}{dt}=75\ cm/s=0.75\ m/s$

We need to find the magnitude of induced emf at that instant. Induced emf is given by :

$\epsilon=\dfrac{-d\phi}{dt}$

Where

$\phi$ is the magnetic flux, $\phi=B\times A$

$\epsilon=\dfrac{-d(BA)}{dt}$ , A is the area of cross section

$\epsilon=-\dfrac{-d(B(\pi r^2))}{dt}$

$\epsilon=-2\pi r B(\dfrac{dr}{dt})$

$\epsilon=-2\pi \times 0.016\times 0.8 \times 0.75\ m/s$

$\epsilon=0.0603\ V$

So, the induced emf in the loop is 0.0603 volts. Hence, this is the required solution.

3 0

3 years ago