Answer: 580 x 10^-3 J
Explanation:
0.6mm is 0.6/1000 = 600*10^-6 m
The plate area is .17*.17 = 28.9*10^-3 m^2
Air:
The voltage that can be sustained by 0.60 mm of air dielectric is:
V = 3.0*10^6* 600*10^-6 = 1800 V
The capacitance is:
C = ε*A/d = 8.854*10^-12 * 28.9*10^-3/600*10^-6 = 426*10^-12 F = 426 pF
The energy stored in a capacitor is:
E = (1/2)*C*V^2 = (1/2)*426*10^-12*(1800)^2 = 691*10^-6 J
Teflon:
The voltage is:
V = 60*10^6* 600*10^-6 = 36*10^3 = 36 kV
According to the listed reference, the relative dielectric constant for teflon is 2.1, this figure multiplies the "ε" of free space.
The capacitance is:
C = ε*A/d = 2.1*8.854*10^-12 * 28.9*10^-3/600*10^-6 = 896*10^-12 F = 896 pF
It would have been easier to note that the capacitance is 2.1 times the air-dielectric case.
The maximum energy stored is:
E = (1/2)*C*V^2 = (1/2)* 896*10^-12* (36*10^3)^2 = 580*10^-3 J
Answer: Either of the two
Explanation:
Either of the two - the governed idle spring or the normal primary governor spring can be adjusted first.
The main function of the carburetor is to mix air with fuel.
SBb type spiral. Its a type B because its not too tightly wound but its still too tight to be a type C
Answer:
(a) The resistance of 25m of wire is 3 ohms
(b) the length of this wire that has resistance 22 ohms is 183.33 m
Explanation:
Given;
resistivity of the wire, ρ = 0.12 ohms per meter
(a) The resistance of 25m of wire is calculated as follows;
(b) the length of this wire that has resistance 22 ohms is calculated as;
Answer:
The ball will have a kinetic energy of 0.615 Joules.
Explanation:
Use the kinetic energy formula
The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)
