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morpeh [17]
3 years ago
9

1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)

Chemistry
1 answer:
Mrac [35]3 years ago
3 0

Answer:

Mass = 245.72 g

Explanation:

Given data:

Mass of SrCl₂ react = ?

Mass of H₂SO₄ = 300.0 g

Solution:

SrCl₂  +  2H₂SO₄     →     2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles =  300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and  H₂SO₄.

                   H₂SO₄         :       SrCl₂

                        2             :           1

                      3.1             :         1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

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8 0
3 years ago
Consider the reaction:
goldfiish [28.3K]

Answer:

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Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

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Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)

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Since [PCl₅] = [PCl₅]

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Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

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5 0
3 years ago
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Answer:

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Explanation:

Hello,

In this case, by using the Henderson-Hasselbach equation one can compute the concentration of acetate, which acts as the base, as shown below:

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[base]=1.38[acid]=1.38*0.20M=0.28M

Regards.

6 0
3 years ago
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