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3 years ago

What is the molecular formula of a compound containing 42.17% Chlorine, 57.83% Oxygen, and has a molecular mass of 166 g/mol?

Chemistry

1 answer:

Juliette [100K]3 years ago

6 0

Answer:

C2H4CL2

Explanation:

this is your answer

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If an unknown liquid has a density of 0.756 g/mL and a mass of 2.00 g, what is its volume?

OverLord2011 [107]

Answer:

<h3>The answer is 2.65 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 2 g

density = 0.756 g/mL

So we have

$volume = \frac{2}{0.756} \\ = 2.645502...$

We have the final answer as

Hope this helps you

4 0

3 years ago

Determine the oxidation number of CI element in each of the following species:

labwork [276]

Fbbrnev said he was still in a coma and he said he was still in a coma and

3 0

3 years ago

A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of

Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the reaction between HCl and KOH:

$HCl~+~KOH->~H_2O~+~KCl$

Now for example, we can use a volume of 10 mL of HCl. So, we can calculate the moles using the molarity equation:

$M=\frac{mol}{L}$

We know that $10mL=0.01L$ and we have the concentration of the HCl $0.282M$ , when we plug the values into the equation we got:

$0.282M=\frac{mol}{0.01L}$

$mol=0.282*0.01$

$mol=0.00282$

We can do the same for the KOH values ( $50mL=0.05L$ and $0.141M$ ).

$0.141M=\frac{mol}{0.05L}$

$mol=0.141*0.05$

$mol=0.00705$

So, we have so far 0.00282 mol of HCl and 0.00705 mol of KOH. If we check the reaction we have a molar ratio 1:1, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an excess of KOH. This excess can be calculated if we substract the amount of moles:

$0.00705-0.00282=0.00423mol~of~KOH$

Now, if we want to calculate the pH value we will need a concentration, in this case KOH is in excess, so we have to calculate the concentration of KOH. For this, we already have the moles of KOH that remains left, now we need the total volume:

$Total~volume=50mL+10mL=60mL$

$60mL=0.06L$

Now we can calculate the concentration:

$M=\frac{0.00423mol}{0.06L}$

$M=0.0705$

Now, we can calculate the pOH (to calculate the pH), so:

$pOH=-Log(0.0705)$

$pOH=1.15$

Now we can calculate the pH value:

$14=~pH~+~pOH$

$pH=14-1.15=12.84$

8 0

3 years ago

Lakes can disappear due to *

lesya [120]

Answer:

Drought, resulting in a 65% reduction in water levels.

8 0

3 years ago

For the main group elements( excluding the transition elements) , is it necessary to memorize the type of ion each element makes

vagabundo [1.1K]

Yes, you should memorize them. While it is easy to predict them by looking at a periodic table, you should still have a strong grasp of simpler chemistry such as this before more challenging topics are taught.

3 0

3 years ago