Answer:
d= 64.7 km

displacement vector
Explanation:
total distance = 40 + 30 = 70 km
during 1st flight


during 2nd flight



the two component of r are:


Geographical Direction ![\theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cfrac%7Br_y%7D%7Br_x%7D%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Ctheta%20%3D%2040.9%5E%7Bo%7D)
Displacement d

d= 64.7 km
displacement vector
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Answer:
<h2>9.3kN</h2>
Explanation:
Step one:
given data
mass of bullet= 0.02kg
speed v=700m/s
time taken =1.5ms= 0.0015 seconds
Step two:
we know that from the first law
F=ma-----1 first law of motion
also, we know that
a=v/t----2
put a=v/t in equation 1 we have
F=mv/t
Step three:
substitute our given data to find force
F=0.02*700/0.0015
F=14/0.0015
F=9333.33N
F=9.3kN
<u>The average force exerted is 9.3kN</u>