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Fiesta28 [93]
2 years ago
9

What are accounts for physical properties?

Chemistry
1 answer:
Nezavi [6.7K]2 years ago
3 0
Freezing point, boiling point, melting point, smell, attraction or repulsion to magnets, colour change, and many more examples.
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CORRECT ANSWER GETS BRAINLIEST! PLEASE HELP AND EXPLAIN!!
Anna71 [15]

Answer:

A car stopped at the top of the hill

Explanation:

It's potenial energy because, the car could go down the hill and create kinetic energy. Hope this helps! Please give me brainly it is correct!

3 0
3 years ago
How much concentrated solution would it take to prepare 2.75 L of 0.400 M HCl upon dilution with water
grin007 [14]
Hydrochloric acid is usually purchased in a concentrated form that is 37.0% HCl by mass and has a density of 1.20g/mL. Calculate the molarity of the concd HCl.
1.20 g/mL x 1000 mL x 0.37 x (1/36.5) = about 12 M or so but you do it exactly.

Then mL x M = mL x M
mL x 12 M = 2800 mL x 0.475
Solve for mL of the concd HCl solution.
7 0
2 years ago
Three chemical reactions of ethane?
Otrada [13]

Answer:

1.Hydrogenation of Alkenes and akynes.

2.Reaction of alkylhalides.

3. Halogenation.

6 0
2 years ago
What is the energy of a wave with wavelength of 4.2 x 10-7 m. (Hint: Calculate for frequency first.)
erik [133]

Answer:

Option B. 4.74×10¯¹⁹ J.

Explanation:

The following data were obtained from the question:

Wavelength (λ) = 4.2×10¯⁷ m

Energy (E) =.?

Next, we shall determine the frequency of the wave. This can be obtained as follow:

Wavelength (λ) = 4.2×10¯⁷ m

Velocity (v) = constant = 3×10⁸ m/s

Frequency (f) =.?

v = λf

3×10⁸ = 4.2×10¯⁷ × f

Divide both side by 4.2×10¯⁷

f = 3×10⁸ / 4.2×10¯⁷

f = 7.143×10¹⁴ s¯¹

Therefore, the frequency of the wave is 7.143×10¹⁴ s¯¹.

Finally, we shall determine the energy of the wave using the following formula

E = hf

Where

E is the energy.

h is the Planck's constant

f is the frequency

Thus, the enery of the wave can be obtained as follow:

Frequency (f) = 7.143×10¹⁴ s¯¹.

Planck's constant = 6.63×10¯³⁴ Js

Energy (E) =..?

E = hf

E = 6.63×10¯³⁴ × 7.14×10¹⁴

E = 4.74×10¯¹⁹ J

Therefore, the energy of the wave is 4.74×10¯¹⁹ J.

5 0
3 years ago
Describe how atomic emission spectrums came about, and what they say about atoms/electrons.
algol [13]

Answer:

Atomic emission spectrum came out by a series of colored lines

Explanation:

When electricity is passing through an element or when it is viewing through a prism, a unique spectra of light emitted by an element is called atomic emission spectra. They are acting as an element of finger print because they are unique.  When we are seeing a set of colored lines or a black background  , it is an emission spectrum. If we are watching black lines on a colored background it is absorption spectrum.  In electromagnetic spectrum the visible portion are the colors.

In nucleus electrons can exist in some areas are known as shells. Shell corresponds an energy level that is designed by a quantum number n. The lowest energy level electrons are close to the nucleus.

An atom is shone by light, its electrons absorbs photons and it gain energy, and jump to higher level.

8 0
2 years ago
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