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olya-2409 [2.1K]
4 years ago
7

What happens to the molarity of bleach when you prepare a solution using 1 gallon of water and 5 table spoons of bleach (sodium

hypochlorite)?
Chemistry
1 answer:
son4ous [18]4 years ago
6 0

Answer:

Due to the presence of caustic soda in sodium hypo chlorite, the pH of the water is increased. When sodium hypo chlorite dissolves in water, two substances form, which play a role in for oxidation and disinfection. These are hypochlorous acid (HOCl) and the less active hypochlorite ion (OCl-).

Explanation:

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What is the Molar Mass of C3H6OS. <br>​
Tju [1.3M]

Answer:

90.16 g/mol

Explanation:

6 0
3 years ago
Which of the following steps correctly converts 3 moles of fluorine to an equivalent number of particles of fluorine?
Mrrafil [7]
Multiply 3 by the atomic mass of fluorine, forgive me if I’m wrong
4 0
3 years ago
Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or
Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water K_{\rm w} gives a relationship between \rm [H_3O^{+}] and \rm [OH^{-}]:

K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}].

The exact value of K_{\rm w} depends on the temperature. Under \rm 25^{\circ}C, K_{\rm w} \approx 1^{-14}.

The question states that \rm [H_3O^{+}] = 3.9\times 10^{-4}\; M. As a result,

\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}.

  • A solution is acidic if \rm [H_3O^{+}] > [OH^{-}].
  • A solution is neutral if \rm [H_3O^{+}] = [OH^{-}].
  • A solution is acidic if \rm [H_3O^{+}] < [OH^{-}].

\rm [H_3O^{+}] > [OH^{-}] for this solution. As a result, this solution is acidic.

8 0
3 years ago
How many moles are in 78.8 g of potassium sulfite?​
exis [7]

Answer:

158.2598

Explanation:

158.2598 moles are in 78.8 g of potassium sulfite

CARRY ON LEARNING

6 0
3 years ago
Doreen schmidt is a chemist. she needs to prepare 3232 ouncesounces of a 1010​% hydrochloric acid solution. find the amount of 1
slavikrds [6]
24 ounces of 8% solution and 8 ounces of 16% solution to create 32 ounces of 10% solution.  
OK. We need 32 ounces of 10% solution and we have 16% and 8% solutions available. So let's set up an equation to solve. I'll use the variable X to represent the amount of 8% solution needed. 
X*0.08 + (32-X)*0.16 = 32*0.10 
 Now simplify and solve.
 X*0.08 + (32-X)*0.16 = 32*0.10
 X*0.08 + 32*0.16 - X*0.16 = 32*0.10
 X*0.08 - X*0.16 = 32*0.10 - 32*0.16
 X(0.08 - 0.16) = 32(0.10 - 0.16)
 X(-0.08) = 32(-0.06)
 X = 32(-0.06)/(-0.08)
 X = 24 
 So we need 24 ounces of 8% solution and (32 - 24) = 8 ounces of 16% solution.
6 0
3 years ago
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