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olya-2409 [2.1K]
3 years ago
7

What happens to the molarity of bleach when you prepare a solution using 1 gallon of water and 5 table spoons of bleach (sodium

hypochlorite)?
Chemistry
1 answer:
son4ous [18]3 years ago
6 0

Answer:

Due to the presence of caustic soda in sodium hypo chlorite, the pH of the water is increased. When sodium hypo chlorite dissolves in water, two substances form, which play a role in for oxidation and disinfection. These are hypochlorous acid (HOCl) and the less active hypochlorite ion (OCl-).

Explanation:

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The modern periodic table has groups.
Snezhnost [94]
Three groups

gases, metals, metalliods/nonmetals
3 0
3 years ago
Which of the following elements has the greatest metallic character?<br> Rb<br> Mo<br> Au<br> B
jek_recluse [69]

Answer:

Au. fifififiof

Explanation:

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5 0
3 years ago
Read 2 more answers
Any substance which yields a hydrogen ion when placed in a water solution is call an——-
lidiya [134]

it is A Acid

Explanation : Any substance that yields a hydrogen ion when placed in a water solution is called an acid. According to Arrhenius theory of Acids and Bases, Acids are those substances which on dissociation in solution generates ions. Whereas a Base is a substance that dissociates in the solution to produce ions.

6 0
3 years ago
Calculate the volume of the acid solution and the volume of the conjugate base solution that would be needed to prepare a buffer
bogdanovich [222]

Answer:

Explanation:

This can be contradictory, depending on whether the 0.1 M

is the total species concentration or the concentration of each of the two components. I'll consider this to be the former...

VA− = 9.125 mL

VHA = 15.875 mL

The Henderson-Hasselbalch equation is:

pH = pKa + log [A−][HA]

We have a pH 4.5

solution of acetic acid and acetate, so from there we can get the ratio of weak acid to conjugate base:

[A−][HA]=10

pH − pKa = 104.5 − 4.74 = 0.5754

Now, if the total concentration is

0.10 M , then:

[HA] + [A−] 0.5754

[HA] = 0.10 M

⇒[HA] = 0.10 M 1.0000 +0.5754

= 0.0635 M

−−−−−−−−

⇒[A−] = 0.0365 M

−−−−−−−−

and these concentrations are AFTER mixing. Since the total volume is 50 mL , or 0.050 L, the mols of each component (which are constant!) are:

nA − = 0.0365 molL × 0.050L =

0.001825 mols

−−−−−−−−−−−−

nHA = 0.0635 molL × 0.050L =

0.003175 mols

−−−−−−−−−−−−

So, if both of the starting concentrations were

0.20 M, we can find the volume they each start with:

VA − = 1 L0.20mols

A− × 0.001825mols A− = 0.009125 L = 9.125 mL

−−−−−−−−

VHA = 1 L 0.20 mols HA × 0.003175

mols HA = 0.015875 L = 15.875 mL

−−−−−−−−−

And this should make sense, because the total starting volume is

25.000 mL , the total ending volume is twice as large; the total species concentration is half the concentration that both species started with.

6 0
2 years ago
The following chemical reaction takes place in aqueous solution: 2FeBr3 (aq) + 3Na2S (aq) → Fe2S3 (s) + 6NaBr (aq) Write the net
lakkis [162]
A net ionic equation simply means to cancel out any ions which appear on both sides of the chemical equation that are not involved in the reaction - they're called spectator ions. 
We'll first write out the full ionic equation, showing all ions and compounds formed, then rewrite and not include spectator ions.

2FeBr3(aq) + 3Na2S(Aq) --> Fe2S3(s) + 6NaBr(aq)   [original eqation]

2Fe3+(aq) + 6Br-(aq) + 3Na+(aq) + 3S2-(aq)--> Fe2S3(s)+6Na+(aq) + 6Br-(aq)
[full ionic equation]

2Fe3+(aq) + 3S2-(aq)--> Fe2S3(s)   [net ionic equation]

notice that Br- and Na+ appear unreacted on both sides of the full ionic equation, so they cancel out and do not appear in the net ionic.

*Please give me a 'brainliest' if you can! Thanks!


5 0
3 years ago
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