A because the dot nearst to a
Answer:

Explanation:
The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.
The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:

where
m = 20.1 kg is his mass
is the acceleration due to gravity
h = 662 m is the initial heigth
The final mechanical energy (at the bottom) is equal to his kinetic energy:

where
v = 7.12 m/s is the final speed of the parachutist
Therefore, the energy lost due to air friction is:

Answer:
A.) 4 revolution
B.) 0.2 revolution
C.) 4 seconds
D.) 2.75 m/s
Explanation:
Given that a merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m
Solution
1 revolution = 2πr
Where r = 1.75m
A. How many revolutions will it make in 3 minutes?
(2π × 1.75) / 3
10.9955 / 3
3.665 RPM
Number of revolution = 15 / 3.665
Number of revolution = 4 revolution
B. How many revolutions will it make in 10.0 seconds?
First convert 10 seconds to minutes
10/60 = 0.167 minute
(2π × 1.75) / 0.167
10.9955 / 0.167
65.973
Number of revolution = 15 / 65.973
Number of revolution = 0.2 revolution
C. How long does it take for a person to make 1 complete revolution?
15 = 1 / t
Make t the subject of formula
t = 1/15
t = 0.0667 minute
t = 4 seconds
D. What is the velocity in m/s of person standing on its edge?
Velocity in m/ s will be:
Velocity = (15 × 2pi × r) / 60
Velocity = 164.9334 / 60
Velocity = 2.75 m/s
Answer:

Explanation:
Additional information:
<em>The ball has charge </em>
<em>, and the ring has positive charge </em>
<em> distributed uniformly along its circumference. </em>
The electric field at distance
along the z-axis due to the charged ring is

Therefore, the force on the ball with charge
is


and according to Newton's second law

substituting
we get:

rearranging we get:

Now we use the approximation that
<em>(we use this approximation instead of the original </em>
<em> since </em>
<em>, our assumption still holds )</em>
and get


Now the last equation looks like a Simple Harmonic Equation

where

is the frequency of oscillation. Applying this to our equation we get:


Answer:
The branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.