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kogti [31]
3 years ago
8

Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic energy is the energy of motion, and

potential energy is stored energy.
Raise the pendulum again. Carefully watch the Energy Graph on the left. It shows the amount of energy the pendulum has as it moves.

At the top of its swing, does the pendulum have kinetic energy or potential energy?
PLEASE HELP!
Physics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

Potential energy only

Explanation:

at the top of its swing the pendulum stops moving , (therefore it has no KINETIC energy)  thus all of the energy is stored as potential energy.

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Bowl of water A bowl full of water is sitting out in a pouring rainstorm. Its surface area is 500 cm2. The rain is coming straig
vova2212 [387]

Answer: 4.9 x 10-3 N

Explanation:

A = 500cm^2 = 5 x 10^-2 m^2

V = 5 m/s

R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec

Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3

For the stationary bowl,

dm/dt =pAv= RA

F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N

Bowl moving upwards to speed u = 2 m/s

dm/dt = pA ( v + u) / v

F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N

5 0
3 years ago
Suppose the maximum safe intensity of microwaves for human exposure is taken to be 1.39~\mathrm{W/m^2}1.39 W/m ​2 ​​ . If a rada
wolverine [178]

Answer:

0.763 m

Explanation:

Intensity I = power P ÷ area A of exposure (spherical area of propagation)

I = P/A

A = P/I

Power = 10.0 W

Intensity = 1.39 W/m^2

A = 10/1.39 = 7.19 m^2

Area A = 4¶r^2

7.19 = 4 x 3.142 x r^2

7.19 = 12.568r^2

r^2 = 7.19/12.568 = 0.57

r = 0.753 m

3 0
3 years ago
Please send help my way. 10 points to the brainliest
antoniya [11.8K]
The possible units for impulse would be:
<span>(N. s)
</span><span>(kg. m/s)</span>

4 0
4 years ago
Newton's second law is a major part of mechanics. However, it does have its limitations. Under what condition does the second la
uysha [10]

Answer:

It a major part of mechanics what do you think.

Explanation:

7 0
3 years ago
Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg
KengaRu [80]

Answer

given,

speed of car = 60 km/hr

                     = 60 x 0.278 m/s

                     = 16.68 m/s

radius of the tire = 25 cm = 0.25 m

time taken to stop = 6 s

average acceleration = ?

\omega = \dfrac{v}{R}

\omega = \dfrac{16.68}{0.25}

\omega =66.72 rad/s

average acceleration= \dfrac{\Delta \omega}{\Delta t}

                                   =  \dfrac{66.72}{6}

                                   = 11.12 rad/s²

correct answer option D

b) length of sea saw = 10 m

mass of jack = 100 Kg

mass of Jill = 60 Kg

Let y be the distance from the Jack. To balance the seesaw moment on both side should balance each other about fulcrum

   now,

     100 x y = 5 x 60

             y = 3 m

the correct answer is option B

   

4 0
3 years ago
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