Answer: 4.9 x 10-3 N
Explanation:
A = 500cm^2 = 5 x 10^-2 m^2
V = 5 m/s
R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec
Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3
For the stationary bowl,
dm/dt =pAv= RA
F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N
Bowl moving upwards to speed u = 2 m/s
dm/dt = pA ( v + u) / v
F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N
Answer:
0.763 m
Explanation:
Intensity I = power P ÷ area A of exposure (spherical area of propagation)
I = P/A
A = P/I
Power = 10.0 W
Intensity = 1.39 W/m^2
A = 10/1.39 = 7.19 m^2
Area A = 4¶r^2
7.19 = 4 x 3.142 x r^2
7.19 = 12.568r^2
r^2 = 7.19/12.568 = 0.57
r = 0.753 m
The possible units for impulse would be:
<span>(N. s)
</span><span>(kg. m/s)</span>
Answer:
It a major part of mechanics what do you think.
Explanation:
Answer
given,
speed of car = 60 km/hr
= 60 x 0.278 m/s
= 16.68 m/s
radius of the tire = 25 cm = 0.25 m
time taken to stop = 6 s
average acceleration = ?


average acceleration= 
= 
= 11.12 rad/s²
correct answer option D
b) length of sea saw = 10 m
mass of jack = 100 Kg
mass of Jill = 60 Kg
Let y be the distance from the Jack. To balance the seesaw moment on both side should balance each other about fulcrum
now,
100 x y = 5 x 60
y = 3 m
the correct answer is option B