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kogti [31]
2 years ago
8

Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic energy is the energy of motion, and

potential energy is stored energy.
Raise the pendulum again. Carefully watch the Energy Graph on the left. It shows the amount of energy the pendulum has as it moves.

At the top of its swing, does the pendulum have kinetic energy or potential energy?
PLEASE HELP!
Physics
1 answer:
mihalych1998 [28]2 years ago
7 0

Answer:

Potential energy only

Explanation:

at the top of its swing the pendulum stops moving , (therefore it has no KINETIC energy)  thus all of the energy is stored as potential energy.

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Bella makes the 6.1m distance to her food bowl in 8.8 seconds what is her average velocity
storchak [24]
Bella’s average velocity is about 0.693 meters per second.

To find the average velocity, you must divide the distance by the change in time, which should look like v=d/t

Here is how you set up the equation-
v=6.1/8.8

Once you divide 6.1 meters by 8.8 seconds, you should get a number that looks like 0.69318182.... however, I just rounded it to 0.693 meters per second. You can round it to whatever you like.

Hope this helped! If you have any questions about what I mentioned in my answer or explanation, feel free to comment on my answer and I’ll try to get back to you!
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25.16 what is the reaction product of acetic acid and ethylamine at room temperature?
Ne4ueva [31]

The ammonium salt of acetic acid is the reaction product of acetic acid and ethylamine at room temperature

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7 0
1 year ago
Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t
LiRa [457]

Answer:

The minimum coefficient of friction is 0.544

Solution:

As per the question:

Radius of the curve, R = 48 m

Speed of the car, v = 16 m/s

To calculate the minimum coefficient of static friction:

The centrifugal force on the box is in the outward direction and is given by:

F_{c} = \frac{mv^{2}}{R}  

f_{s} = \mu_{s}mg

where

\mu_{s} = coefficient of static friction

The net force on the box is zero, since, the box is stationary and is given by:

F_{net} = f_{s} - F_{c}  

0 = f_{s} - F_{c}  

\mu_{s}mg = \frac{mv^{2}}{R}  

\mu_{s} = \frac{v^{2}}{gR}  

\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544  

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