All categories

3 years ago

What does newton's third law say about why momentum is conserved in collisions?

Chemistry

2 answers:

matrenka [14]3 years ago

8 0

Answer: Option (A) is the correct answer.

Explanation:

According to Newton's third law of motion, when force is exerted by one body to second body then the second body will also exert a force equal in magnitude and opposite in direction on the first body.

For example, when we hit a wall with our leg then the wall also applies a force on our leg and thus, our leg gets hurt.

Hence, we can conclude that newton's third law says that momentum is conserved in collisions because equal forces act in equal times, so the change in momentum for both objects must be equal.

ASHA 777 [7]3 years ago

6 0

I took the test and can confirm that the answer is A.

You might be interested in

How many moles of CO are there in 1.40 x 10^24 molecules.

viva [34]

Answer:

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (1.40×10^24)/(6.02×10^23)

Mole = 2.33mole

6 0

3 years ago

As the frequency of a wave increases, the energy...

gizmo_the_mogwai [7]

The energy decreases

8 0

3 years ago

If the pOH of a cesium hydroxide solution is known to be 4.00. what is the (OH)? *Please round your answer to the appropriate nu

Snowcat [4.5K]

Answer:

i going to be aniston i would say take a gess

4 0

2 years ago

A Brønsted-Lowry acid Question 9 options: A) has a lower pH than vinegar. B) is any species that donates a proton. C) is any spe

rusak2 [61]

Answer:

B) is any species that donates a proton.

7 0

2 years ago

In another experiment, a 0.150 M BF4^-(aq) solution is prepared by dissolving NaBF4(s) in distilled water. The BF4^-(aq) ions in

Ilia_Sergeevich [38]

Answer:

A) Forward rate = 1.1934 × 10^(-4) M/min

B) I disagree with the claim

Explanation:

A) We are told that [HF] reaches a constant value of 0.0174 M at equilibrium.

The reversible reaction given to us is;

BF4-(aq) +H20(l) → BF3OH-(aq) + HF(aq)

From this, we can see that the stoichiometric ratio is 1:1:1:1

Thus, concentration of [BF4-] is now;

[BF4-] = 0.150 - 0.0174

[BF4-] = 0.1326 M

From the rate law, we are told the forward rate is kf [BF4-].

We are given Kf = 9.00 × 10^(-4) /min

Thus;

Forward rate = 9.00 × 10^(-4) /min × (0.1326M)

Forward rate = 1.1934 × 10^(-4) M/min

(B) The student claims that the initial rate of the reverse reaction is equal to zero can't be true because at equilibrium, rates for the forward and reverse reactions are usually equal.

Thus, I disagree with the claim.

3 0

2 years ago