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3 years ago

9

What is the torque in ( lbs-ft ) of a man pushing on a wrench with 65 lbs of force 8 unches from the nut / bolt he is trying to

turn?

1 answer:

Mademuasel [1]3 years ago

4 0

Explanation:

The torque $\tau$ is given by

$\tau=Fd = (65\:\text{lbs})(\frac{8}{12}\:\text{ft}) = 43.3\:\text{lbs-ft}$

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Hitting a ball off a tee would be considered which of the following?

Keith_Richards [23]

I think the answer would be B

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4 years ago

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nata0808 [166]

Answer:

$f=1.98\times 10^5\ Hz$

Explanation:

The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by :

$B=1.2\times 10^{-6}\sin [2\pi (\dfrac{z}{240}-\dfrac{10^7t}{8})]$ .....(1)

The general equation of the magnetic field wave is given by :

$B=B_o\sin (kz-\omega t)$ ....(2)

Equation (1) is in form of equation (2), if we compare equation (1) and (2) we find that,

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$f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{10^7}{8\times 2\pi}\\\\f=1.98\times 10^5\ Hz$

So, the frequency of the wave is $1.98\times 10^5\ Hz$

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3 years ago

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Naddik [55]

Answer:

23.5

Explanation:

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3 years ago

A car accelerates uniformly from rest and reaches a speed of 22.5 m/s in 8.96 s. Assume the diameter of a tire is 58.9 cm. (a) F

Murljashka [212]

Answer:

54.4747649021

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Explanation:

Acceleration

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Number of revolutions is 54.4747649021

Angular speed is given by

$\omega=\dfrac{v}{r}\\\Rightarrow \omega=\dfrac{22.5}{0.589}\\\Rightarrow \omega=38.2003395586\ rad/s$

The final angular speed is 38.2003395586 rad/s

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4 years ago

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