Answer:
solute
Explanation:
The substance that dissolves is called the solute. The substance that dissolves it is called the solvent.
If a solution of potassium hydroxide is mixed and or chemically reacted with sulphuric acid, the type of reaction that will occur is a Neutralization reaction or a unique type of a Double Replacement Reaction.
Solution = Double Replacement.
Energy transferred into the system is wonderful due to the fact the system ends up with greater strength while energy transferred out from the machine is negative, because the device finally ends up with much less energy.
In defining work, we awareness at the outcomes that the system (e.g. an engine) has on its surroundings. for this reason we outline work as being fine when the gadget does work at the environment (strength leaves the machine). If work is completed at the gadget (energy added to the machine), the work is bad.
The classical sign convention states that warmth switch into a device and work produced with the aid of it are tremendous, while heat transfer faraway from a device and work produced on it is negative.
Q is wonderful if warmness is added into the device from the surroundings. The take a look at tube would feel cooler if the response had been being finished in one. If the surroundings is tormented by the machine, work is poor. This indicates that energy is escaping the system.
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Answer:
ΔG = - 442.5 KJ/mol
Explanation:
Data Given
delta H = -472 kJ/mol
delta S = -108 J/mol K
So,
delta S = -0.108 J/mol K
delta Gº = ?
Solution:
The answer will be calculated by the following equation for the Gibbs free energy
G = H - TS
Where
G = Gibbs free energy
H = enthalpy of a system (heat
T = temperature
S = entropy
So the change in the Gibbs free energy at constant temperature can be written as
ΔG = ΔH - TΔS . . . . . . (1)
Where
ΔG = Change in Gibb’s free energy
ΔH = Change in enthalpy of a system
ΔS = Change in entropy
if system have standard temperature then
T = 273.15 K
Now,
put values in equation 1
ΔG = (-472 kJ/mol) - 273.15 K (-0.108 KJ/mol K)
ΔG = (-472 kJ/mol) - (-29.5 KJ/mol)
ΔG = -472 kJ/mol + 29.5 KJ/mol
ΔG = - 442.5 KJ/mol
