Answer:
Explanation:
Given that,
Frequency f = 5 kHz = 5000Hz
Voltage V=45V
Current In inductor I = 65mA
I = 65 × 10^-3 = 0.065A
We want to find inductance L
We know that the reactive inductance cam be given as
XL = 2πFL
Where
XL is reactive inductance
F is frequency
L is inductance
Then,
L = XL/2πF
From ohms law
V = IR
We can calculate the receive reactance of the inductor
V = I•XL
Then, XL = V/I
XL = 45/0.065
XL = 692.31 ohms
Then,
L = XL/2πF
L = 692.31/(2π×5000)
L = 0.02204 H
Then, L = 22.04 mH
The inductance of the inductor is 22.04mH
Answer:
450m
Explanation:
You would use the equation x-x0=0.5(v0+v)t as you have the time and velocities. x-x0(Change in position/displacement)=0.5(0+30)30. The distance will be 450m.
Density, streak, and geochemical signature through use of inductively coupled plasma mass spectrometry or Fourier transform infrared spectroscopy
Option C homie. 0.00001 C at 2 meters is 0.225 N
Answer:
<h3>3.33m/s</h3>
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the velocities
v is the final velocity
Given
m1 = 50g
u1 = 10m/s
m2 = 100g
u2 = 0m/s (stationary ball)
Required
Common velocity v
Substitute
50(10) + 100(0) = (50+100)v
500 = 150v
v = 500/150
v = 3.33m/s
Hence the velocity of each ball immediately after the collision is 3.33m/s