Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
0
Step-by-step explanation:
The only value that would make sense is if at least one of the variables (A , B , C , D) is 0 (if not all of them). When multiplied, the answer will still be 0, thereby making the equation true.
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Answer:
Answer is below
Step-by-step explanation:
Yes, the graph would still be a function, but a different function than if the values were all different. This would cause two of the values to be the same and have no slope on the line. Before, the function was quadratic, but now it would be quadratic until the two values are equal.
Y = 48 becuase you travelled the amount of minuets 45 x
The answer would be A. There is a phase shift to the left. Because you are adding pi/6.
