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aleksklad [387]
3 years ago
5

Required information

Physics
1 answer:
ValentinkaMS [17]3 years ago
6 0

Answer:

The net force is 4.6 [N]

Explanation:

If the sled moves freely and with constant speed at that time, it is because there is no acceleration, therefore applying newton's second law of motion we can say that the sum of the forces acting on the sled is equal to zero.

The force that counteracts friction and wind must be directed in the opposite direction to these two.

- 4 - 0.6 + F = 0

F = 4.6 [N]

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A block is attached to a spring, with spring constant k, which is attached to a wall. it is initially moved to the left a distan
Ghella [55]

Answer:

x(t) = d*cos ( wt )

w = √(k/m)

Explanation:

Given:-

- The mass of block = m

- The spring constant = k

- The initial displacement = xi = d

Find:-

- The expression for displacement (x) as function of time (t).

Solution:-

- Consider the block as system which is initially displaced with amount (x = d) to left and then released from rest over a frictionless surface and undergoes SHM. There is only one force acting on the block i.e restoring force of the spring F = -kx in opposite direction to the motion.

- We apply the Newton's equation of motion in horizontal direction.

                             F = ma

                             -kx = ma

                             -kx = mx''

                              mx'' + kx = 0

- Solve the Auxiliary equation for the ODE above:

                              ms^2 + k = 0

                              s^2 + (k/m) = 0

                              s = +/- √(k/m) i = +/- w i

- The complementary solution for complex roots is:

                              x(t) = [ A*cos ( wt ) + B*sin ( wt ) ]

- The given initial conditions are:

                              x(0) = d

                              d = [ A*cos ( 0 ) + B*sin ( 0 ) ]

                              d = A

                              x'(0) = 0

                              x'(t) = -Aw*sin (wt) + Bw*cos(wt)

                              0 = -Aw*sin (0) + Bw*cos(0)

                              B = 0

- The required displacement-time relationship for SHM:

                               x(t) = d*cos ( wt )

                               w = √(k/m)

3 0
3 years ago
Whenever one object exerts a force on another object, the second object exerts a force of the same magnitude on the first object
Naddik [55]

Answer:

A

Explanation:

Newton third law of motion state that action and reaction are equal and opposite

6 0
3 years ago
Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he p
Tomtit [17]

Answer:

B- He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.

Explanation: Dissolving Salt in water is a Chemical Change, Because the Salt arrangement is different in solid state than dissolved in water. As we can see in the image below, once the Salt is dissolved, it is separated into its ions, Na+ and Cl- Now, The evaporation process is a physical change, because the water doesn´t change its configuration H20 and it only changes its form, as we can see in the image below.

6 0
3 years ago
Read 2 more answers
The mechanical energy of a 2kg body is 35J and its potential energy is 10J calculate speed energy​
Anna11 [10]

Answer:

20

Explanation:

20 multiplied by 2

hope i hv answered ur question

5 0
3 years ago
What is a lenticular (S0) galaxy? A galaxy with a disk and central bulge like a spiral galaxy, but with no spiral arms A galaxy
RSB [31]

Answer:

A galaxy with a disk and central bulge like a spiral galaxy, but with no spiral arms

Explanation:

A Lenticular galaxy is a kind of galaxy intermediate between elliptical galaxy and a spiral galaxy in the Morphological classification system of galaxies. They have a central bulge or disc just like a Spiral galaxy but lacks the arms of spiral galaxy. If looked edge on they appear to be spiral and if looked face on they appear to be elliptical.

The absence of spiral arms can be attributed to the absence of star formation. They mainly consists of ageing stars.

6 0
4 years ago
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