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3 years ago

Required information

Physics

1 answer:

ValentinkaMS [17]3 years ago

6 0

Answer:

The net force is 4.6 [N]

Explanation:

If the sled moves freely and with constant speed at that time, it is because there is no acceleration, therefore applying newton's second law of motion we can say that the sum of the forces acting on the sled is equal to zero.

The force that counteracts friction and wind must be directed in the opposite direction to these two.

- 4 - 0.6 + F = 0

F = 4.6 [N]

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In what ways would organisms living in very deep water need to be specialized?

Nady [450]

Organisms living in great depths of water bodies like oceans and lakes need to be adapted for two (2) things especially; high water pressure and vision in darkness

The water column above from deep in the water can cause lots of hydrostatic pressure on the organisms’ cells. Also the fact that light cannot penetrate to great depth of water due to diffusion means the organisms must live in darkness.

Explanation:

It has been shown that cells from Piezophile bacteria have a high percentage of fatty acids in their membranes to prevent the cells from compacting solid from the high pressure.

Most of the organisms are also detritivores and use chemosynthesis for the autotrophs because light cannot reach these depths and hence photosynthesis is not possible. Organisms with eye vision are adapted to high wavelength light that can at least reach greater depths before diffusing. Nonetheless natural selection would favour use of sight for most organisms in this benthic region.

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3 years ago

Bradley gets an x-ray at a radiology clinic that employs its own technologists and radiologists. Would the coder at the clinic r

KengaRu [80]

Answer:

Explanation:

If Bradley examination was done and interpreted in the same facility, the radiologist code is used example- procedure code 72100- Radiologic examination, spine, lumbosacral, 2 or 3 views is reported.

if the X-ray was taken by Dr X but Dr X does not read or interpret the image but forward it to the radiologist for initial report, then a 26- modifier is used. E.g A reports by the technologist would be, procedure code 72050-Radiologic examination, spine, cervical, 2 or 3

views or 72050- TC in certain situations and the consulting radiologist would report 72050-26.

if Bradley’s x-ray were sent to an independent radiologist for interpretation, then the procedure code 76140 is used in reporting.

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2 years ago

planet a has twice the mass of planet b. from this info what can we conclude about the acceleration due to gravity at the surfac

tangare [24]

Answer: acceleration due to gravity of planet a would be twice that of planet b. Given that the radius are thesame.

Explanation:

Acceleration due to gravity is as a result of the gravitational force of attraction of a planet to its centre.

g = GM/r^2

Where;

g = acceleration due to gravity

G = gravitational constant

M = mass of planet

r = radius of planet

Given that the two planet have the same radius, if the mass of planet a is twice the mass of planet b the the acceleration due to gravity of planet a would be twice that of planet b, because acceleration due to gravity is directly proportional to the mass of the planet.

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3 years ago

You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1

drek231 [11]

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

The given parameters;

Mass of the pendulum, = M
Length of the pendulum, = L
Initial angular speed, $\omega _i$ = 1 rad/s

The moment of inertia of the rod about the end is given as;

$I_i = \frac{1}{3} ML^2$

The moment of inertia of the rod between the middle and the end is calculated as;

$I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}$

Apply the principle of conservation of angular momentum as shown below;

$I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f$