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Bess [88]
3 years ago
11

B^2 - c^2 -10(b-c) Factor Completely people are getting this wrong I need help please

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0
The factor that is the first one is the most important
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A piston is seated at the top of a cylindrical chamber with radius 3 cm when it starts moving into the chamber at a constant spe
dlinn [17]

Answer:

1. V = πr²h

2. dv/dt = πr²dh/dt

3. dv/dt = 113.04

Step-by-step explanation:

We have these information

Radius R = 3cm

Height = h

Volume = V

We have been given dh/dt = 4cm

1.

An equation relating V, r, h

Volume of cylinder = πr²h

2.

The related rates equation

dv/dt = πr²dh/dt

dv/dt = π3²dh/dt

3. Continuing from number 2 above, we have

dv/dt = π3²dh/dt

= π9x4

= 3.14x9x4

= 113.04

These are the answers to the questions

4 0
3 years ago
Find the horizontal asymptote of of the graph of y=(-3x^6+5x+3)/9x^6+6x+4
NNADVOKAT [17]

Answer:

  y = -1/3

Step-by-step explanation:

As x gets large, the value of the expression approaches the ratio of the highest-degree terms in numerator and denominator:

  y = -3x^6/(9x^6) = -3/9

  y = -1/3

5 0
3 years ago
Can someone please answer this im stuck
Nastasia [14]
I think its A not sure though
5 0
2 years ago
Read 2 more answers
A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho
MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

8 0
3 years ago
Read 2 more answers
Mike drew a quadrilateral with four right angles. What shape could be drawn?
Darya [45]
There could be 2 possible shapes that could’ve been drawn.

A rectangle, or a square.

All of their angles are 90° angles, which are right angles.


Hope this helped!
5 0
3 years ago
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