What keeps both the cars pressed down on the road?

Three particles are placed in the xy plane. A 50-g particle is located at (3, 4) m, and a 40-g particle is positioned at ( 2, 6)

oksano4ka [1.4K]

Answer:

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Explanation:

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7 0

3 years ago

A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3

Ivan

Answer:

$B_{m}=1.4333*10^{-8}T$

Explanation:

Given data

Ex = Ey = 0

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

To find

The amplitude of the magnetic field component

Solution

The electric field is given by:

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

Where Em=4.3 V/m

The magnitude of magnetic field is given by:

$B_{m}=\frac{E_{m}}{c}$

Where Em is amplitude of electric field and c is speed of light.

Substitute the given values

So

$B_{m}=\frac{4.3V/m}{3.0*10^{8}m/s }\\B_{m}=1.4333*10^{-8}T$

7 0

3 years ago

Final naïve case: If the highest-pitch string on the piano is made of spring steel (density = 7800 kg/m3) with a diameter of 1/3

oksano4ka [1.4K]

Answer:

The linear density is $K = 3.863 *10^{-3 } \ kg/m$

Explanation:

From the question we are told that

The density of steel is $\rho = 7800 \ kg/m^3$

The diameter of the string is $d = 0.794 \ mm = 7.94 *10^{-4} \ m$

The radius of the string is evaluated as $r = \frac{D}{2} = \frac{7.94 *10^{-4}}{2} = 3.97*10^{-4} \ m$

The volume of the string is mathematically evaluated as

$V = \pi * r ^2 * L$

Now assuming that the length of the string is L = 2 m

So

$V = 3.142 * (3.97 *10^{-4})^2 * (2)$

$V = 9.9041 *10^{-7} \ m^3$

Then the mass of the string would be

$m = \rho * V$

substituting value

$m = 7800*9.904 14 *10^{-7}$

$m = 7.73*10^{-3} \ kg$

Looking at the question we see that the unit of the linear density is $\frac{kg}{m}$

Hence the linear density is evaluated as

$K = \frac{m}{L}$

substituting value

$K = \frac{7.73 *10^{-3}}{2}$

$K = 3.863 *10^{-3 } \ kg/m$

8 0

3 years ago

A 24 resistor, an inductor with a reactance of 12 , and a capacitor with a reactance of 10 are in series across a 60 V 50 Hz sou

sukhopar [10]

Answer:

A⋅24=24A

12=24A

10=24A

a⋅(60V)⋅(50Hz)=3000aVHz

Explanation:

3 0

3 years ago

When a wave is acted upon by an external damping force what happens to the energy of the wave

Nimfa-mama [501]

Answer:

A-the energy of the wave decreases gradually

Explanation:

when a wave is acted upon by an external damping force the energy of the wave decreases gradually.

The energy degrades into the form of heat which is considered to be of less value and use. The reason is because it disperses and spreads more widely.

So therefore it end up as heat with a little sound but that is close to none because that too disperses into heat i.e. decreased form of energy.

4 0

4 years ago

What keeps both the cars pressed down on the road? ​

What keeps both the cars pressed down on the road?