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3 years ago

Two pieces of flint rock produce a visible spark

Physics

1 answer:

noname [10]3 years ago

4 0

<span>(3) electromagnetic energy and internal energy</span>

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The moon is 3x10^5 km away from Nepal and the mass of the moon is 7x10^22 kg. Calculate the force with which the Moon pulls ever

hammer [34]

Answer:

Approximately $5.19 \times 10^{-5}\; \rm N$ .

Explanation:

Let $G$ denote the gravitational constant. ( $G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}$ .)

Let $M$ and $m$ denote the mass of two objects separated by $r$ .

By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:

$\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}$ .

In this question: $M = 7 \times 10^{22}\; \rm kg$ is the mass of the moon, while $m = 1\; \rm kg$ is the mass of the water. The two are $r = 3\times 10^{5}\; \rm km$ apart from one another.

Important: convert the unit of $r$ to standard units (meters, not kilometers) to reflect the unit of the gravitational constant $G$ .

$\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m$ .

$\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}$ .

5 0

3 years ago

A car is traveling along a straight road at a velocity of +30.0 m/s when its engine cuts out. For the next 1.79 seconds, the car

Tanzania [10]

Answer:

first value+2nd +3rd

Explanation:

thug life and there

8 0

3 years ago

In what scenario might a red ball appear black?

zhuklara [117]

A scenario a red ball might appear black is when there is a shadow in front of it.or when the ball is in a dark place.

3 0

4 years ago

A place that is warm year round and near the equator would most likely have what type of climate?

ratelena [41]

It's geography,
tropical climate

6 0

4 years ago

fomenos

Answer:

The correct option is;

(A) 1 m/s

Explanation:

Given that Ramu and Somu are running towards North with 3 m/s and 4 m/s respectively.

Their friend Srinu is running towards South with a speed of 2 m/s

The magnitude of the relative velocity of Ramu with respect to Ramu is found as follows;

Velocity of Ramu = 3 m/s North ↑

Velocity of Srinu = 2 m/s South↓ = -2 m/s North ↑

Relative velocity of Ramu to Srinu = Velocity of Ramu North + Velocity of Srinu North

Relative velocity of Ramu to Srinu = 3 m/s + (-2) m/s = (3 - 2) m/s = 1 m/s

Relative velocity of Ramu to Srinu = 1 m/s.

4 0

4 years ago