When one wave crest overlaps the crest of another and they add together what happens to the amplitude?
2 answers:
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Answer:
Stretch can be obtained using the Elastic potential energy formula.
The expression to find the stretch (x) is
Explanation:
Given:
Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.
To find: Elongation in the spring (x).
We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).
The formula to find EPE is given as:
Rewriting the above expression in terms of 'x', we get:
Example:
If EPE = 100 J and spring constant, k = 2 N/m.
Elongation or stretch is given as:
Therefore, the stretch in the spring is 10 m.
So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.
Answer:
<em>Height = 5.65 km</em>
Explanation:
is the circumference or we can say measures the boundary of hemisphere of friction-less ice that he is sitting on.
So, the height will be = 2 x 3.14 x (30)^2 = 5654.7 m = 5.65 km
Answer:
a) The linear acceleration of the car is , b) The tires did 7.46 revolutions in 2.50 seconds from rest.
Explanation:
a) A tire experiments a general plane motion, which is the sum of rotation and translation. The linear acceleration experimented by the car corresponds to the linear acceleration at the center of the tire with respect to the point of contact between tire and ground, whose magnitude is described by the following formula measured in meters per square second:
Where:
- Magnitude of the radial acceleration, measured in meters per square second.
- Magnitude of the tangent acceleration, measured in meters per square second.
Let suppose that tire is moving on a horizontal ground, since radius of curvature is too big, then radial acceleration tends to be zero. So that:
Where:
- Angular acceleration, measured in radians per square second.
- Radius of rotation (Radius of a tire), measured in meters.
Given that and
. The linear acceleration experimented by the car is:
The linear acceleration of the car is .
b) Assuming that angular acceleration is constant, the following kinematic equation is used:
Where:
- Final angular position, measured in radians.
- Initial angular position, measured in radians.
- Initial angular speed, measured in radians per second.
- Angular acceleration, measured in radians per square second.
- Time, measured in seconds.
If ,
,
, the final angular position is:
Let convert this outcome into revolutions: (1 revolution is equal to 2π radians)
The tires did 7.46 revolutions in 2.50 seconds from rest.