Hi there!
We must begin by converting km/h to m/s using dimensional analysis:

Now, we can use the kinematic equation below to find the required acceleration:
vf² = vi² + 2ad
We can assume the object starts from rest, so:
vf² = 2ad
(17.22)²/(2 · 75) = a
a = 1.978 m/s²
Now, we can begin looking at forces.
For an object moving down a ramp experiencing friction and an applied force, we have the forces:
Fκ = μMgcosθ = Force due to kinetic friction
Mgsinθ = Force due to gravity
A = Applied Force
We can write out the summation. Let down the incline be positive.
ΣF = A + Mgsinθ - μMgcosθ
Or:
ma = A + Mgsinθ - μMgcosθ
We can plug in the given values:
22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))
A = 46.203 N
<span>It takes only one atom to make hydrogen; however, hydrogen is commonly found as H2, meaning two atoms make up hydrogen. Because of this, hydrogen is known as a diatomic element
The answer is prob A.1 but you didnt' give me a formula.</span>
Answer:
The work done by the weightlifter, W = 700 J
The power of the weightlifter, P = 350 watts
Explanation:
A weightlifter lifts a set of weights a vertical distance, s = 2 m
The force exerted to lift the weight, F = 350 N
The work done by the body is defined as the product of the force applied by the body to the displacement it caused.
W = F x s
= 350 N x 2 m
= 700 J
The work done by the weightlifter, W = 700 J
The time taken by the weightlifter to lift the weight, t = 2 s
The power is defined as the rate of body to do work. It is given by the equation,
P = W / t
= 700 J / 2 s
= 350 watts
Hence, the power of the weightlifter, P = 350 watts
Answer:
Explanation:
Given
mass of first 
mass of second 
Distance of
from origin 
Distance of
from origin 
Moment of inertia is given by multiplication of mass and square of distance





<span>v=40 <span><span>cm</span>s</span> speed of wave</span>
<span>λ=8 cm wavelength</span>
<span>f=? frequency of wave</span>
<span>v=λ⋅f</span>
<span>40=8⋅f</span>
<span>f=<span>408</span></span>
<span>f=5 <span>s<span>−<span>1 is the answer </span></span></span></span>