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Nimfa-mama [501]
3 years ago
6

Element X has five valence electrons, element Y has one valence electron, and element Z has one valence electron. Which two of t

hese elements are most likely to have similar properties? Explain your answer.
Physics
2 answers:
Grace [21]3 years ago
5 0
The two elements would be element Y and element Z. They both have one valence electron. This means that their bonding properties would be similar because both of them can donate 1 electron. Since both of them have one valence electron, one can assume that they also belong in the same group. 
Tomtit [17]3 years ago
4 0

Answer:

Element Y and element Z

Explanation:

One of the criteria for grouping the elements in the periodic table is according to their valence electrons.

If several elements have the same amount of valence electrons, they belong to the same group.

If they have the same configuration of valence electrons, then electronegativity, atomic radius, ionization energy, among others. It will be similar.

Element Y and element Z have the same number of valence electrons, then they will be located in the same group, and share similar periodic properties

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const2013 [10]

Answer:

The Forces of Flight

At any given time, there are four forces acting upon an aircraft.  

These forces are lift, weight (or gravity), drag and thrust. Lift is  

the key aerodynamic force that keeps objects in the air. It is the  

force that opposes weight; thus, lift helps to keep an aircraft in  

the air. Weight is the force that works vertically by pulling all  

objects, including aircraft, toward the center of the Earth. In order  

to fly an aircraft, something (lift) needs to press it in the opposite  

direction of gravity. The weight of an object controls how strong  

the pressure (lift) will need to be. Lift is that pressure. Drag is a  

mechanical force generated by the interaction and contract of a  

solid body, such as an airplane, with a fluid (liquid or gas). Finally,  

the thrust is the force that is generated by the engines of an  

aircraft in order for the aircraft to move forward.

Explanation:

5 0
2 years ago
Pablo's engineering team has developed a new material that is strong enough to withstand major impacts, including bullets, witho
marin [14]

Answer:

the answer is c

Explanation:

4 0
3 years ago
A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The
Damm [24]

Answer:

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

Explanation:

3 0
3 years ago
The<br> is the time it takes for a wave to complete one cycle.
hichkok12 [17]

Answer:

Time Period

Explanation:

3 0
2 years ago
Read 2 more answers
A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc
marta [7]
This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so: 

v_{d} =  \frac{J}{n\left | q \right |}

<span>The current I is any motion of charge from one region to another, so this is given by:

</span>I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)

The magnitude of the current density is:

J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})

Being:

A=2mm^{2} = 2x10^{-6}m^{2}
<span>
Finally, for the drift velocity magnitude vd, we find:

</span>v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
6 0
2 years ago
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