Question

A 23.0 kg child is riding a playground merry-go-round that is rotating at 30.0 rpm. What centripetal force, in N, must she exert to stay on if she is 2.00 m from its center

Answer 1

Answer:

The value is  $F = 454 \ N$

Explanation:

From the question we are told that

   The mass of the child is  $m = 23.0 \ kg$

   The angular velocity is  $w = 30 \ rpm = \frac{2 \pi * 30 }{60} = 3.142 \ rad/s$

   The distance from the center is  $r = 2.0 \ m$

Generally the centripetal force is mathematically represented as

       $F = m * w^2 * r$

=>   $F = 23 * 3.142 ^2 * 2$    

=>   $F = 454 \ N$