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pishuonlain [190]
3 years ago
14

Tell me the name please​

Chemistry
1 answer:
natima [27]3 years ago
5 0

Answer:

molecules

Explanation:

they are molecule

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What is the freezing point of a solution of 0.5 mol of LiBr in 500 mL of water? (Kf = 1.86°C/m) –1.86°C –7.44°C –5.58°C –3.72°C
tresset_1 [31]

Answer:

  • Last choice: <em><u>- 3.72°C</u></em>

Explanation:

The freezing point depression in a solvent is a colligative property: it depends on the number of solute particles.

The equation to predict the freezing point depression in a solvent is:

  • ΔTf = Kf × m × i

Where,

  • ΔTf is the freezing point depression of the solvent,
  • m is the molality,
  • Kf is the cryoscopic molal constant of the solvent, and i is the Van'f Hoff factor, which is the number of ions produced by each unit formula of the ionic compound.

The calcualtions are in the attached pdf file. Please, open it by clicking on the image of the file.

Download pdf
6 0
3 years ago
How many moles of a gas sample are in a 10.0 L container at 373 K and 203 kPa? the gas constant is 8.31 L -kPa/ mol-K.
Zepler [3.9K]
I believe the answer is 0.33
5 0
3 years ago
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Provide the quantum numbers for each electron in the element gadolinium
Basile [38]
Atomic # 64
electronic configuration is *[Xe] 6s^2 4f^8
n = 4
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mℓ<span> = -3</span>
ms<span> = -½</span>
7 0
3 years ago
In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2
Delvig [45]
<span>2HI + Ca(OH)2 --> Cal + 2H2O. According to stoichiometry, 2 moles of HI reacts with 1 mole of Ca(OH)2. Therefore, 1.2 moles of HI will react with = 1.2/2 = 0.6 moles of Ca(OH)2. Hope this helps.</span>
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3 years ago
What is the pH of an aqueous solution with [H3O+] = 6×10−12 M ?
hram777 [196]

Answer: pH = 10.92

Explanation:

To determine the pH of an aqueous solution, we use the following mathematical relation; pH = - log [H3O+]

                                           = - log (6 x 10∧ -12)

                                           = 12 - 1.08

                                   pH =  10.92

                                           

4 0
3 years ago
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