Charge and uncharged particles
There are 4 atoms of sodium in the formula of sodium sulfite.
<h3 /><h3>Number of atoms at sodium</h3>
There are 4 atoms of sodium in the formula of sodium sulfite because 4 digit is placed before sodium which shows the number of sodium atom present in the molecule while on the other hand, 2 is placed in front of sulfur which tells us that 2 atoms of sulfur is used in the making of sodium sulfite.
<h3>Reasons of war</h3>
In this excerpt, Paine is attempting to convince the readers that we have righteous reasons to justify supporting the war. We should participate and take part in the war in order to defend ourselves and our country but avoid offensive war to gain financial benefits.
Learn more about war here: brainly.com/question/1174232
Learn more: brainly.com/question/26123703
Atomic mass W = 183.84 u.m.a
183.84 g ----------- 6.02x10²⁴ atoms
?? g ---------------- 2.1x10²⁴ atoms
2.1x10²⁴ x 183.84 / 6.02x10²⁴ =
3.860x10²⁶ / 6.02x10²⁴ = 641.30 g
hope this helps!
Answer:
1
Explanation:
There is only one calcium atom because the subscript 3 applies only to the oxygen. Outside of the parentheses, the subscript 2 only applies to the chlorate ion. Therefore, there is only one calcium atom because there are no coefficients and subscripts. (Also drawing it out will help)
Answer:
33.95 grams of NaN3
Explanation:
Number of moles of NaN3 = mass (m)/MW = m/65 mole
I mole of NaN3 requires 22.4L air bag
m/65 mole of NaN3 required 11.7L
22.4m/65 = 11.7
22.4m = 65×11.7
22.4m = 760.5
m = 760.5/22.4 = 33.95grams of NaN3
