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3 years ago

PLEASE HELPPPP!!!!!!!!!!

Physics

2 answers:

son4ous [18]3 years ago

5 0

Answer:

I think its B

Explanation:

marysya [2.9K]3 years ago

3 0

I’m pretty sure it’s B :)

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A police car waits in hiding slightly off the highway. A speeding car is spotted by the police car traveling at speed s = 27.6 m

andriy [413]

Answer:

$t=\frac{2s}{a}=25.56s$

Explanation:

The distance traveled by the speeding car will be $d_s=st$ , where $s=27.6m/s$ .

The distance traveled by the police car will be given by the formula:

$d=v_{0}t+\frac{at^2}{2}$ , where $a=2.16m/s^2$ and $v_0=0m/s$ since it departs from rest, thus having $d=\frac{at^2}{2}$ .

The police car will reach the speeding car when those distances are the same, or $s=d$ , so we will have:

$st=\frac{at^2}{2}$

Which means:

$t=\frac{2s}{a}$

This is the expression asked, but we can use our values:

$t=\frac{2s}{a}=\frac{2(27.6m/s)}{(2.16m/s^2)}=25.56s$

6 0

3 years ago

Can someone help me PLEASE? I need to finish this because I have more homework and I need to go to bed

Dafna1 [17]

When the computer is on the circuit has positive and negative charges it will move fluenlty to get the power when it is in on position.

8 0

3 years ago

Air pressure is 1.0 · 105 N/m2, air density is 1.3 kg/m3, and the density of soft drinks is 1.0 · 103 kg/m3. If one blows carefu

natita [175]

Answer:

v = 27.456 m/s

Explanation:

The support pressure needed of the water in the straw can be calculated by the formula

Given that,

P = r*g*h

= 1000*9.8*0.05 Pa.= 490 Pa

This pressure is compensated by 0.5*r*v^2 of the air,

Hence,

0.5*1.3*v^2 = 490

velocity of air blown into the straw =

v = 27.456 m/s

8 0

3 years ago

A capacitor is charged until it holds 5.0 j of energy. it is then connected across a 10-kω resistor. in 13.6 ms , the resistor d

prohojiy [21]

Answer:

The capacite is C=5.32 uF using the equations of voltage and energy in capacitance

Explanation:

The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J

Using:

$V_{t}= V_{o}e^{\frac{-t}{R*C} }$

Voltage in this case is the energy dissipated so

$E_{t}= E_{o}e^{\frac{-t}{R*C} }$

$\frac{\sqrt{E_t} }{\sqrt{E_o} } = e^{\frac{-t}{R*C} }$

$\frac{\sqrt{3 J} }{\sqrt{5J} } = e^{\frac{-13.6ms}{10kw*C} }$

Using the equation to find capacitance

$ln 0.775= e^{\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\ln(0.775)= ln * e^{\frac{-13.6 x10^{3s} }{10x10^{3}*C }} \\\\ln(0.775)= {\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\C= \frac{-13.6 x10^{-3} }{10x10x^{3}*ln(0.775) }$

$C= 5.32x10^{-6}$ F

C= 5.32 uF because u is the symbol for micro that is equal to $10^{-6}$

8 0

3 years ago

A lizard accelerates from 2 m/s to 10 m/s in 4 seconds. what is the lizard average acceleration

VLD [36.1K]

Acceleration = (change in speed) / (time for the change)

change in speed = (ending speed) - (starting speed)

change in speed = (10 m/s) - (2 m/s) = 8 m/s

Acceleration = (8 m/s) / (4 sec)

Acceleration = (8/4) (m/s²)

<em>Acceleration = 2 m/s²</em>

8 0

3 years ago