(a) 2NO(g) + O₂(g) ⇄2NO₂(g)kp
(b) 2N₂O(g)⇄2NO(g) + N₂(g) kp
(c) N₂(g) + O₂(g)⇄ 2NO(g) kp
Now A is
2NO +O₂⇄2NO₂
ΔG° =ΔG° products - ΔG reactants
=2× 51.3-(256.6)
-70.6kJ/mol.
ΔG° = -RT Inkp
-70.6 = -8.314 ×10⁻³ ˣ 298.15 ˣInkJ
InkJ = 28.48
kp=2.34 ˣ 10¹²
B is
ΔG° = 2× 86.6 - 2 × 104.2 = -35.2
-35.2 = 8.314 × 10⁻³ ˣ 298.15 ˣInkJ
InkJ = 14.2
kp = 1.47ˣ 10⁶
C is
It is also similar
kp = 4.62 ˣ 10⁻³I
Answer:
0.915 Nm
Explanation:
1 revolution = 2π rad
We can use the following equation of motion to find out the acceleration acting on the disk
where ![\omega v = 2.5 rad/s is the final angular velocity of the disk, [tex]\omega_0](https://tex.z-dn.net/?f=%5Comega%20v%20%3D%202.5%20rad%2Fs%20is%20the%20final%20angular%20velocity%20of%20the%20disk%2C%20%5Btex%5D%5Comega_0)
= 0 rad/s is the initial velocity of the can when it starts from rest, 
is the angular distance traveled, 
is the angular acceleration of the disk, which we care looking for:
The moment of inertia of the solid disk is:
where m is the mass and R is the radius of the disk
The net torque applied is
Complete question:
A uniform electric field is created by two parallel plates separated by a
distance of 0.04 m. What is the magnitude of the electric field established
between the plates if the potential of the first plate is +40V and the second
one is -40V?
Answer:
The magnitude of the electric field established between the plates is 2,000 V/m
Explanation:
Given;
distance between two parallel plates, d = 0.04 m
potential between first and second plate, = +40V and -40V respectively
The magnitude of the electric field established between the plates is calculated as;
E = ΔV / d
where;
ΔV is change in potential between two parallel plates;
d is the distance between the plates
ΔV = V₁ -V₂
ΔV = 40 - (-40)
ΔV = 40 + 40
ΔV = 80 V
E = ΔV / d
E = 80 / 0.04
E = 2,000 V/m
Therefore, the magnitude of the electric field established between the plates is 2,000 V/m
Answer:
please mark brainlist
Explanation:
Initial speed u=80 km/h=80×185=22.22 m/s
Final speed v=60 km/h=60×185=16.67 m/s
Using v=u+at
Or 16.67=22.22+α×5
⟹ a=−1.1 m/s2
