7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J
8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m
9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333
Answer:
- The distance between the charges is 5,335.026 m
Explanation:
To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:

where k is Coulomb's constant,
and
are the charges and d is the distance between the charges.
Working a little the equation, we can take:


And this equation will give us the distance between the charges. Taking the values of the problem

(the force has a minus sign, as its attractive)




And this is the distance between the charges.
It’s solved by using a pretty standard formula for efficiency.
Answer:
100s
Explanation:
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