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wlad13 [49]
3 years ago
9

how many liters of radon gas would be in 3.43 moles at standard temperature and pressure (273K and 100 kPa)?

Chemistry
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:

V = 0.0007678398L

Explanation:

Given parameters:

Number of moles of gas = 3.43moles

Temperature = 273k

pressure = 100kPa = 100000Pa

Unknown:

Volume of gas = ?

Solution

The gas is at standard temperature and pressure, this implies we can use the ideal gas equation to solve for the unknown.

Mathematically, the law is expressed as:

                               PV = nRT

The unknown here is the Volume, V. We know the other parameters.

       P = pressure on the gas

      n = number of moles

       R = gas constant=0.082

       T = temperature

now, we have to make V the subject of the expression:

                   V = \frac{nRT}{P}

                   V = \frac{3.43 x 0.082 x 273}{100000}

                   V = 0.0007678398L

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