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3 years ago

What are characteristics of a chemical equation?

1 answer:

N76 [4]3 years ago

8 0

Answer: e. Number 1 and 3
Reasoning: Correct formulas are necessary to get the correct outcome. No matter is created or destroyed, the equation must be balanced.

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Carbon dating requires that the object being tested contain

luda_lava [24]

Answer:

Organic Material

Explanation:

Carbon Dating is the process in which the age of a piece of organic matter is determined by the proportions of carbon isotopes it contains.

4 0

2 years ago

What is the main point of mutation ? <br> quick please !!

Ede4ka [16]

Answer: type of mutation that causes the replacement of a single base nucleotide with another nucleotide of the genetic material, DNA or RNA. The term point mutation also includes insertions or deletions of a single base pair.

Explanation:

5 0

3 years ago

Read 2 more answers

When one moves from

Reptile [31]

The answer is a bc it decreases

7 0

3 years ago

Read 2 more answers

1. What is the MAIN reason the Phoenicians are important for marine science?

Vikki [24]

Answer:

Explanation:

The Phoenicians contributed to ocean exploration by establishing the first trade routes throughout the Mediterranean, even as far north as Great Britain.

3 0

2 years ago

La rapidez a la que cantan los grillos de árbol es de 2.0 ×102 veces por minuto a 27°C, pero es sólo de 39.6 veces por minuto a

Lorico [155]

Answer:

51096J/mol = Energía de activación para el proceso del canto

Explanation:

Podemos solucionar este problema usando una forma de la ecuación de Arrhenius:

$Ln\frac{K_2}{K_1} = \frac{-Ea}{R} (\frac{1}{T_2} - \frac{1}{T_1} )$

Donde K representa la velocidad de reacción (En este caso, la velocidad a la que cantan los grillos), Ea es la energía de activación, R la constante de los gases (8.314J/molK) y T representa la temperatura absoluta de 1, el estado inicial y 2, el estado final.

Estado inicial: K1 = 2.0x10²; T1 = 27°C + 273.15 = 300.15K

Estado final: K2 = 39.6; t2 = 5°C + 273.15 = 278.15K

Reemplazando en la ecuación:

$Ln\frac{39.6}{2.0x10^2} = \frac{-Ea}{8.314J/molK} (\frac{1}{278.15K} - \frac{1}{300.15K} )\\\\-1.6195 = \frac{-Ea}{8.314J/molK}*2.6351x10{-4}K{-1}$

<h3>51096J/mol = Energía de activación para el proceso del canto</h3>

5 0

2 years ago