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lilavasa [31]
3 years ago
12

What are characteristics of a chemical equation?

Chemistry
1 answer:
N76 [4]3 years ago
8 0
Answer: e. Number 1 and 3
Reasoning: Correct formulas are necessary to get the correct outcome. No matter is created or destroyed, the equation must be balanced.
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Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.
Serjik [45]

I think the correct answer would be the last one.

7 0
3 years ago
Read 2 more answers
15 POINTS!!!! Please answer 1-8
Effectus [21]
1. combustion
2. succession
3. condensation
4. precipitation
5. pioneer species
6. decomposition
7. evaporation
8. nitrogen fixation
4 0
3 years ago
Suppose you have a mixture of copper sulfate (CuSO4) and azulene (C10H8, you may wish to know the structure of azulene). Both co
iVinArrow [24]

Answer:

Aqueous layer (1 M HCI)

Explanation:

First of us I want to remind you of the cliché in chemistry that like dissolves like. In solvent extraction, a mixture is dissolved in a system consisting of two immiscible solvents. One layer is organic while the other layer is aqueous.

Polar substances partition in the aqueous layer while nonpolar substances partition in the organic layer.

Since Copper sulfate is ionic, we will find it in the aqueous layer according to the old chemistry cliche.

3 0
3 years ago
Determine the pH of the resulting solution if 25 mL of 0.400 M strychnine (C21H22N2O2) is added to 50 mL of 0.200 M HCl? Assume
DIA [1.3K]

Answer:

pH = 4.56

Explanation:

The strychnine reacts with HCl as follows:

C₂₁H₂₂N₂O₂ + HCl ⇄ C₂₁H₂₂N₂O₂H⁺ + Cl⁻

<em />

For strychnine buffer:

pOH = 5.74 + log [C₂₁H₂₂N₂O₂H⁺] / [C₂₁H₂₂N₂O₂]

Initial moles of C₂₁H₂₂N₂O₂ are:

0.025L * (0.400 mol / L) = 0.01 moles C₂₁H₂₂N₂O₂

And of HCl are:

0.05L * (0.200 mol / L) = 0.01 moles HCl

That means after the reaction, you will have just 0.01 moles of C₂₁H₂₂N₂O₂H⁺ in 50mL + 25mL = 0.075L. And molarity is:

[C₂₁H₂₂N₂O₂H⁺] = 0.01 mol / 0.075L = 0.1333M

This conjugate acid, is in equilibrium with water as follows:

C₂₁H₂₂N₂O₂H⁺(aq) + H₂O(l) ⇄ C₂₁H₂₂N₂O₂ + H₃O⁺

<em />

<em>Where Ka = Kw / Kb = 1x10⁻¹⁴ / 1.8x10⁻⁶ = 5.556x10⁻⁹</em>

<em />

Ka is defined as:

Ka = 5.556x10⁻⁹ = [C₂₁H₂₂N₂O₂] [H₃O⁺] / [C₂₁H₂₂N₂O₂H⁺]

In equilibrium, concentrations are:

C₂₁H₂₂N₂O₂ = X

H₃O⁺ = X

C₂₁H₂₂N₂O₂H⁺ = 0.1333M - X

Replacing in Ka expression:

5.556x10⁻⁹ = [X] [X] / [0.1333M - X]

7.39x10⁻¹⁰ - 5.556x10⁻⁹X = X²

7.39x10⁻¹⁰ - 5.556x10⁻⁹X - X² = 0

Solving for X:

X = - 2.72x10⁻⁵M → False solution. There is no negative concentrations

X = 2.72x10⁻⁵M → Right solution.

As H₃O⁺ = X

H₃O⁺ = 2.72x10⁻⁵M

And pH = -log H₃O⁺

<h3>pH = 4.56</h3>
4 0
3 years ago
Calculate the weight of keame if he has potential energy of 67J and standing at a hieght of 10m.(take g100m/s)​
DanielleElmas [232]

Answer:

height(h)=10 m

acceleration due to gravity (g)=10 m/s^2

mass (m)=?

potential energy=67

or,mgh= 67

or,m×10×10=67

or,m=67/100

or,m=0.67 kg

Therefore,m= 670 grams

7 0
3 years ago
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