Molarity of 275 mL of solution containing 135 mol of glucose.
<h3>What is molarity?</h3>
Molar concentration (also known as molarity, quantity concentration, or substance concentration) is a measure of the concentration of a chemical species in a solution, specifically of a solute, in terms of amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.
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Answer:
The bismuth sample.
Explanation:
The specific heat 
of a substance (might not be a metal) is the amount of heat required for heating a unit mass of this substance by unit temperature (e.g., 
.) The formula for specific heat is:
,
where
is the amount of heat supplied.
is the mass of the sample. 
is the increase in temperature.
In this question, the value of (amount of heat supplied to the metal) and (mass of the metal sample) are the same for all four metals. To find (change in temperature,) rearrange the equation:
,
.
In other words, the change in temperature of the sample, can be expressed as a fraction. Additionally, the specific heat of sample, , is in the denominator of that fraction. Hence, the value of the fraction would be the largest for sample with the smallest specific heat.
Make sure that all the specific heat values are in the same unit. Find the one with the smallest specific heat: bismuth (
.) That sample would have the greatest increase in temperature. Since all six samples started at the same temperature, the bismuth sample would also have the highest final temperature.
Answer:
C6H12O6 —> 2C2H5OH + 2CO2
Explanation:
The equation for the reaction is given below:
C6H12O6 —> C2H5OH + CO2
We can balance the equation above as follow:
There are 12 atoms of H on the left side and 6 atoms of the right side. It can be balance by putting 2 in front of C2H5OH as shown below:
C6H12O6 —> 2C2H5OH + CO2
There are 6 atoms of C on the left side and 5 atoms on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C6H12O6 —> 2C2H5OH + 2CO2
Now the equation is balanced.
