Question

Find the 64th term of the arithmetic sequence -28,-13,2

Answer 1

Answer:

$a_{64}=917$

Step-by-step explanation:

Given that,

The arithmetic sequence is :

-28,-13,2

First term = -28

Common difference = -13-(-28) = 15

We need to find the 64th term of the sequence. The nth term of the sequence is given by :

$a_n=a+(n-1)d$

Put all the values,

$a_{64}=-28+(64-1)15\\\\=917$

So, the 64th term of the sequence is equal to 917.